5. Select a suitable universal beam to support the loads shown below in figure 8 if a factor of safety of 8 is to be used. (futs = 450 MPa; fy = 300 MPa) 12 kN/m 35 kN 15 kN 3 m 1 m 1 m Figure 8
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- A 0.5kg weight is hung from the end of a cantilever beam, causing a vertical displacement of y = -0.01 inches relative to no load. The weight is increased to 1.0kg. What is the new displacement relative to no load? Typed and correct answer please. I ll rateRepeat Problem 11.2-3 assuming that R= 10 kN · m/rad and L = 2 m.Problem 1: Slab design using the ACI moment coefficients Design the continuous slab shown using the ACI moment coefficients assuming the concrete weighs 24 kN/m3 and that a service live load of 15 kN/m is to be supported. The slabs are built integrally with the end supports, which are spandrel beams. fy= 420 MPa and f'c = 28 MPa. Draw a plan and section showing all reinforcements along the slab. E 7m - 6 m + 7m --
- Problem #8: For the beam and loading shown below compute the state of stress at point B (components of the 3x3 matrix), report your answer in ksi to two decimal places. 1.5 in 1.5 in B l in F= 5 kip 3 in 1 in 15 in Fx = 4 kip 3 in Fy = 3 kipRequlred Informatlon A cantilevered beam is loaded as shown. The cross section at the wall is shown, with points of interest A (at the top). B (at the center), and C(midway between A and B). - 200 mm- 50 mm B 50 mm Cross section at wall where F= 2.2 kN NOTE: This is a multi-part question. Once an answer is submitted, you will be unable to return to this part. Calculate the magnitudes of the stresses acting on the stress elements. Do not neglect transverse shear stress. The magnitude of stresses acting on the stress elements are as follows: At element A, MPa and TA= MPa At element B. OB- MPa and T8= MPа At element C. MPa and IC= MPaQuestion 5 Find the supportive force system for the cantilever beam shown pinned at C. Given data: Point load, Not yet answered P=380 N and distributed load, w=80 N/m. Marked out of 5.00 on 7 m 2 m A 5 m- 5 m- Supportive force system Ax= Ay= Сх- N Су- By= N
- A flanged wooden shape is used to support the loads shown on the beam. The dimensions of the shape are shown in the second figure. Assume LAB - 8 ft, Lac-3 ft. Lco=3 ft. Loe-3 ft. Pc-2070 lb. Pe- 1830 lb. WAB=930 lb/ft, b₁-9 in., b₂-2 in., b3-6 in., dj-2 in., d₂-8 in, dj-2 in. Consider the entire 17-ft length of the beam and determine: (a) the maximum tension bending stress oy at any location along the beam, and (b) the maximum compression bending stress oc at any location along the beam. WAS LAB B Lac by C LCD D dj Loc E O. Ask1. For the same beam used in IC-13, determine the jump in shear stress at the web-flange junction (at point A). V = 20KN. A 200 mm 20 mm B 200 mm 20 mm 300 mm 2. Now cut off the bottom flange and recalculate the maximum shear stress. (Remove the bottom flange so that the beam has a T-shaped cross-section.)Required Information NOTE: This is a multi-part question. Once an answer is submitted, you will be unable to return to this part. A truss of a power transmission line tower is shown. Given loading of L = 1.2 kN. 1.60 m -2.21 m- -2.97 m- -2.21 m- D All R F L L P 1.20 m L 1.20 m KN (Click to select) 0.60 m The portion of truss shown represents the upper part of a power transmission line tower. Determine the force in each of the members located above HUJ. State whether each member is in tension (7) or compression (C). The force in member AB (FAB) is KN (Click to select) The force in member AC (FAC) is The force in member DF (FDA) is The force in member EF (FER) is The force in member BD (FBD) is The force in member DE (FDE) is The force in member BE (FB) is The force in member BC (FBC) is The force in member CE (FCE) is The force in member CH (FCH) is The force in member EH (FEH) is The force in member EJ (FE) is KN (Click to select) V KN (Click to select) $0.60 m 10.60 m KN (Click to…
- 0.3m 40 KN Icm 5cm 7cm 0,5m 5cm Icm 10 kNm 0.2m Find deflection of the beam at the point where 40kN force is acting and the slope at the supports.determine reaction A (in kN, roundiff to 2 decimal places) for the loaded beam in the figure.3-12 5) Use the method of sections to find the true magnitude and direction in bar DB of the truss. Hint( Joint C is in equilibrium) B A 45° 4' 4' D -100 lbs FREE BODY DIAGRAM LOADED SECTION True magnitude and direction of DB by section analysis