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- Calculate the solubility of Fe2S3 in water. For H2S, K1=10-7 and K2=10-13,(pKps Fe2S3 =88). then kps= 10-8828: (e) figure 13 attached, (f)The value of 10Dq in the complex K3[Co(C204)3] is ~=-m~=-- the * complex [Co(H20)6]CI3 less than in O bigger than in O equal to O The complex [Co(H20)6]CI2 is less stable than the complex * [Zn(H20)6]CI2 Error |:| true |:| The Na2[CoBr4] complex is more * stable than the K2[CoCl4] complex Error |:| true |:|
- Calçulate Hhe selubility iA Mofeach of Hhe Salts BaSoy ksp zliS Xlo(9) 2 MgCofA)2 ksp= 9.0Xld-12) A9CN kse: 2.0X10(-12). Dfes ksp-3-7 xlo(-19) Ag2sksp:1.6x10(-49)Would you help me with these (5) Thank you.What's More Activity 1. Strength of IMFA and Physical Properties of Covalent Compounds Ror each pair of molecules, identify the one with the higher boiling point (BP), melting noint (MP), viscosity (V), surface tension (ST) and vapor pressure (VP). Briefly explain your choice. BP MP LS H--H H. Methane, CH4 carbon tetrachloride, CC14 S. Dihydrogen sulfide, H2S H. H water, H2O H-0-5-H H-C-C-Ö-H H. Methanol, CH3OH H ethanol, CH3CH2OH H. H. H-C-C=ÖH H-C-C-C-H H. Acetic acid, CH,COOH H. acetone, CH,OCH3 Adapted from Punzalan and Monserat (2016)
- Activity 1. Strength of IMFA and Physical Properties of berrmad suoHInW What's More Activity 1. Strength of IMFA and Physical Properties of d Covalent Compounds For each pair of molecules, identify the one with the higher boiling point (BP), melting soint (MP), viscosity (V), surface tension (ST) and vapor pressure (VP). Briefly explain rour choice. BP MP V ST VP H-C-H CI-C--CI H. :CI Methane, CH4 carbon tetrachloride, CC14 H. H. Dihydrogen sulfide, H2S water, H20 H-C-ö-H H-C-C-ö-H H. H. ethanol, CH3CH:OH Methanol, CH;OH H :O H. H. H-C-C=ÖH H-C-C- C--H Acetic acid, CH3COOH acetone, CH3OCH, Adapted from Punzalan and Monserat (2016) 10SPOT TEST OBSERVATION MATRIX Reagent K.Cro, KSCN NH,OH DMG HCI H,SO, Yellow Clear Clear precipitate No precipitate precipitate No precipitate No reaction precipitate Clear White White Pb(NO,), Orange Dark red Faint orange Clear Clear Clear Fe(NO,), precipitate No precipitate precipitate No reaction No precipitate No precipitate Clear precipitate No precipitate No reaction Yellow no Clear Pink solution Cream White Ni(NO,), solution precipitate No reaction Reddish White Faintly milky white precipitate Clear White No precipitate precipitate precipitate Clear AGNO brownish precipitate precipitate • Clear light yellow No precipitate No precipitate No reaction No precipitate solution Opaque Clear Clear Clear White Ba(NO,), precipitate Undereach reagentindicate whathappened (if anything) when mixed with the metal ion shown on the left. Write balanced reactions to representwhat happenedineach spottest.13.) A mixture containing 50% mole of A is distilled at a temperature T, what is the distillate to residue ratio? А. 1.5 B. 0.33 C. 0.67 D. 2.0 E. 0.50 30 50 60 Mole 5k of A
- Given that Kb For ammonia is 1.8 x 105 and that For hydroxylamine is 1.1 x1D-8 A.What is the ha value For NHyt B. What is the ha value For N3 NO HYou prepare several dilutions of an unknown compound. You measure the pance of each solution at 340 nm using a 1 cm cuvette (your results are listed in the table- -). What is the extinction coefficient (in (Mecm)') of the compound? (Hint: assume that of the individual values contains some degree of experimental error.) entration(µM) Absorbance at 340 nm 0.011 0.023 0.066 0.119 0.189I did not understand soultion for the question.. The relationship between Affinity and Association & Dissociation Constant. Four proteins (A-D) all bind the same ligand (X), with different affinities. For protein A & B we know that they have a binding site for X with a Kd (dissociation constant) of 10⁻⁵and 10⁻⁸ M, respectively. For protein C and D we know that they have a binding site for ligand X with a Ka (association constant) of 10³and 10⁵M, respectively. Which protein has the highest affinity for ligand ? Explain your reasoning. How do you make them all in same constant so that values can be compared and the one with highest Ka or lowest Kd (Highest affinity in both cases) can be ruled out.
