5. (Algebra: solve 2 x 2 linear equations) You can use Cramer's rule to solve the following 2 X 2 system of linear equation: ax + by = e cx + dy = f ed-bf ad - bc y af ec ad - bc Write a program that prompts the user to enter a, b, c, d, e, and f and display the result. If ad- bc is 0, report that The equation has no solution. Enter a, b, c, d, e, f: 9.0, 4.0, 3.0, -5.0, -6.0, -21.0 x is -2.0 and y is 3.0 Enter a, b, c, d, e, f: 1.0, 2.0, 2.0, 4.0, 4.0, 5.0 The equation has no solution Enter Enter

5. (Algebra: solve 2 x 2 linear equations) You can use Cramer's rule to solve the following 2 X 2 system of linear equation: ax + by = e cx + dy = f ed-bf ad - bc y af ec ad - bc Write a program that prompts the user to enter a, b, c, d, e, and f and display the result. If ad- bc is 0, report that The equation has no solution. Enter a, b, c, d, e, f: 9.0, 4.0, 3.0, -5.0, -6.0, -21.0 x is -2.0 and y is 3.0 Enter a, b, c, d, e, f: 1.0, 2.0, 2.0, 4.0, 4.0, 5.0 The equation has no solution Enter Enter

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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In C++ (Algebra: solve 2 × 2 linear equations) You can use Cramer’s rule to solve the following 2 × 2 system of linear equation: ax + by = ecx + dy = fx = (ed - bf) / (ad - bc)y = (af - ec) / (ad - bc) Write a program that prompts the user to enter a, b, c, d, e and f and displays the result. If ad - bc is 0, report that “The equation has no solution”. Sample Run 1 Enter a, b, c, d, e, f: 9.0 4.0 3.0 -5.0 -6.0 -21.0 x is -2 and y is 3 Sample Run 2 Enter a, b, c, d, e, f: 1.0 2.0 2.0 4.0 4.0 5.0 The equation has no solution
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1. Simplify the following expressions. Play with them b) Y = C.(AC.B)
*Modify the program so that the user will error trap for only 1 and 0 as an input. *If the user enters an input other than 1 or 0 display an error message and request the user enter that input again. *Do this for all inputs in the code. # User defined function for logic OR# The function takes two parameters and returns a single intdef OR(a: int, b: int)->int:# If a is equal to 1 return 1if a == 1 :return 1# If b is equal to 1 return 1elif b == 1 :return 1# If a and b is equal to 0 return 0else :return 0 # User defined function for logic NOR# The function takes two parameters and returns a single intdef NOR(a: int, b: int)->int:# If a is equal to 0 and b is also equal to 0 return 1if a == 0 and b == 0 :return 1# If a is equal to 0 and b is equal to 1 return 0elif a == 0 and b == 1 :return 0# If a is equal to 1 and b is also equal to 0 return 0elif a == 1 and b == 0 :return 0# If a is equal to 1 and b is also equal to 1 return 0elif a == 1 and b == 1 :return 0 # User defined…