The matrix A =-2 10 07-2 7 0 has eigenvalues A₁ = 2 and A₂ = 3. An eigenvector for 2 is v₁ =-2 3and 3 has eigenvectors ₂ :-107-53and U37(Use c_1, c_2, and c_3 for C₁, C₂ and C3.)4The vectors ₂ and 3 are linearly indepedentand the defect of A is 0Using 71, 72 and 3, write the general solution z(t) to the system z= Aż :52

(.) Given matrix is, Matrix has eigen values and . An eigen vector for is and has…

5 The matrix A= -2 7 0 has eigenvalues A₁ = 2 and A₂ = 3. An eigenvector for 2 is = 2 1 -2 3 [-2 10 07 ܒ -147 [] The vectors 2 and 3 are linearly indepedent and the defect of A is 0 Using 1, 2 and 3, write the general solution z(t) to the system - At : and 3 has eigenvectors ₂ = -10] -5 and 3 = 3 (Use c_1, c_2, and c_3 for c₁, c₂ and C3.)

5 The matrix A= -2 7 0 has eigenvalues A₁ = 2 and A₂ = 3. An eigenvector for 2 is = 2 1 -2 3 [-2 10 07 ܒ -147 [] The vectors 2 and 3 are linearly indepedent and the defect of A is 0 Using 1, 2 and 3, write the general solution z(t) to the system - At : and 3 has eigenvectors ₂ = -10] -5 and 3 = 3 (Use c_1, c_2, and c_3 for c₁, c₂ and C3.)

Elementary Linear Algebra (MindTap Course List)

8th Edition

ISBN:9781305658004

Author:Ron Larson

Publisher:Ron Larson

Chapter7: Eigenvalues And Eigenvectors

Section7.1: Eigenvalues And Eigenvectors

Problem 65E

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