5 mg of a protein is dissolved in 0.1 mL of distilled water (final volume) to give a final concentration of 0.5 mM. What is the molecular weight (in kDa) of the protein? Show your unit conversion step by step
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5 mg of a protein is dissolved in 0.1 mL of distilled water (final volume) to give a final concentration of 0.5 mM. What is the molecular weight (in kDa) of the protein? Show your unit conversion step by step
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- MCC powder contains 86.6% proteins and WPI powder contains 93.4% protein. Calculate the amount of each protein POWDER required to obtain a 100 ml of 2% (w/v) protein solution.You are creating a standard curve for a protein experiment. You have to stock solution of BS a and would like to obtain dilutions. Explain how you would create a 1:1000 dilution of your protein stock solution.A 1 mL sample of glycogen was calculated to contain 35 µmol (micromole) glucose. To 1 mL of this sample was added 2 mL of 2 M HCL. It was then hydrolysed by boiling the solution for 15 minutes. After boiling the hydrolysate was cooled and made up with H2O to a final volume of exactly 10 mL. The glucose was measured in this solution and found to have a concentration of 570 µg/mL (microgram/milliliter). i) Calculate the mass (mg) of glucose in the 10 mL of hydrolysate. As the 1mL of glycogen sample was made up to a final volume of 10 mL, this mass of glucose was produced by the hydrolysis of the original 1 mL glycogen sample. ii) Calculate the amount (µmol) of glucose produced by the hydrolysis of the glycogen sample. iii) Calculate the purity of the glycogen used in the sample as % Purity = (moles of measured glucose/ moles of calculated glucose in glycogen) *100 iv) state your answer in a complete sentence.
- A 1 mL sample of glycogen was calculated to contain 21 µmol (micromole) glucose. To 1 mL of this sample was added 2 mL of 2 M HCl. It was then hydrolysed by boiling the solution for 15 minutes. After boiling the hydrolysate was cooled and made up with H2O to a final volume of exactly 10 mL. The glucose was measured in this solution and found to have a concentration of 340 µg/mL (microgram/milliliter). i) Calculate the mass (mg) of glucose in the 10 mL of hydrolysate. As the 1 mL of glycogen sample was made up to a final volume of 10 mL, this mass of glucose was produced by the hydrolysis of the original 1 mL glycogen sample. ii) Calculate the amount (µmol) of glucose produced by the hydrolysis of the glycogen sample. iii) Calculate the purity of the glycogen used in the sample as % Purity = (moles of measured glucose/ moles of calculated glucose in glycogen) *100 iv) state your answer in a complete sentence. Show your working out such that the marker can easily understand it.…You want to determine the concentration of NaCl in a water. In preliminary analysis, it appears to be saline water with a NaCl content of approximately 4%. Should you dilute the sample if your titrant has a concentration of 0.1 M and you want to spend 25 mL of sample? Solution: You must dilute approximately ten times, taking 10 mL of sample and making up to 100 mL. In this way, 17.20 mL of titrant will be spent.In the preparation of a standard stock solution for protein analysis, 50 mg of bovine serum albumin (BSA) was dissolved in deionized distilled water to a final volume of 10 mL. What is the weight of BSA in 0.60 mL stock solution?
- You want to determine the concentration of NaCl in a water. In preliminary analysis, it appears to be saline water with a NaCl content of approximately 4%. Should you dilute the sample if your titrant has a concentration of 0.1 M and you want to spend 25 mL of sample?.Prepare standard Fe solutions from a stock solution for which you will need to: determine the concentration in ppm Fe. The exact mass used of the iron-containing compound will be written on the bottle, so you will need to recalculate this with the correct number in the lab, but if,for example, the bottle is labeled 174.3mg of Fe(NH4)2(SO4)2•6H2O in 1.000 liter, what is the concentration in ppm Fe (Hint: this is a concentration in terms of mass, it is not simply 1ppm whole compound = 1ppm Fe.) Thank you!A 0.1 g amine-containing compound is dissolved in water then diluted to 100 mL. You subject it to spectroscopic analysis, in order to get the concentration of amine in this compound. Next, you get 1 mL of the previously diluted sample then dilute it again to 250 mL for measurement. Then, you fill 3/4 of a 1-cm cuvette with this diluted sample, and you run an analysis using an AAS. The recorded absorbance is 0.545 at 410 nm. What is the molecular weight of the compound? (The molar absorptivity is 1.23 x 104 cm-1 mol-1 L.)
- 50 mL of stock solution were taken and added to flask. Then 50 mL of Di water were added to the flask. This is solution 1. Then 50mL of solution 1 were taken and added to a flask and 50 mL of Di water were added to the flask. This is solution 2. Then 50mL of solution 2 were taken and added to a flask and 50 mL of Di water were added to the flask. This is solution 3. Then 50mL of solution 3 were taken and added to a flask and 50 mL of Di water were added to the flask. This is solution 4. Find the concetrations of each solution. Information of stock solution - molar mass- 534.3g/mole 0.587g in MilliQA mixture of ethanol, benzaldehyde and KMnO4 is mixed together. Would you expect a precipitate to form based on the reactants functional groups?A 5.04 g sample of a solid containing Ni is dissolved in 20.0 mL water. A 5.00 mL aliquot of this solution is diluted to 100.0 mL and analyzed in the lab. The analyzed solution was determined to contain 5.53 ppm Ni. Determine the molar concentration of Ni in the 20.0 mL solution. concentration: M Determine the mass, in grams, of Ni in the original sample. mass: g Determine the weight percent of Ni in the sample. weight percent: % * TOOLS x10
