Q: IN Il Il
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Q: For the following compound, HOCH2CH2CH2NH2 a. draw its conjugate acid. b. draw its conjugate base.
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Q: 2. Circle the more acidic compound of each pair. H. ОН ОН ОН но, ОН ГОН ОН ОН Meo
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Q: Label following statement as True or False ? CH2=CH- is the conjugate base of CH2=CH2 .
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Q: Question:- what is the main out put whek heating the fellowing acids Hz Soyacid 2 CH3 CH2 CH CCH3
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Q: `NH2
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Q: 2. Out of each pair of molecules, circle the compound that is the most basic? -HO- HO. NH2
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Q: NH NaOH ? H3O+ NH₂
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Q: 9. For each pair, circle the more acidic compound. CH;CH;OH or CHCH;SH CH;CH;NH2 or CH;CH;CH3
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Q: What is the conjugate base of NH3? None of these NH2- NH3+ NH4OH NH4+
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Q: Circle the stronger acid. 1. HF or HCI 2. H2S or H20 3. CH;=CH2 or CH3-CH3
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Q: a. (i) HOCH2CH2NH2 or (ii)CH3CH2NH2 b. (i) (ii) .N. N- or
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Q: _1) Circle the strongest acid in each pair a. он CH,CHCH, OH CH,CH,NCH,
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Q: which one is more acidic ch3oH or ch3Nh2. explain why please.
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Q: Circle the more acidic compound of each pair. HO но, HO, HO, OH HO, HO, HO, Meo HO. HO, HO. HO. O2N
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Q: Label each statement as True or False CH3CH2- is the conjugate base of CH3CH2+
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- For each molecule below, draw the conjugate acid or conjugate base or both if the molecule hasboth a conjugate acid and a conjugate base (e.g., water).Phenol (shown below) has a pKa10 . a. Based on pKa data, is phenol a stronger or weaker acid than an ordinaryalcohol (e.g.. CH3OH ) or water? b. Draw the conjugate base of phenol (called phenoxide) including allimportant resonance structures. c. Construct an explanation for why phenol is a stronger acid than anordinary alcohol. (You may want to consider first why phenoxide is lowerin PE than methoxide (RO) or hydroxide (HO) .Consider the following bases: a. For each base above, circle the atom/atoms with the highest PE (will release the most P.E.when a lone pair on this atom combines with an H+ ) b. Rank the bases 1 (highest P.E./strongest base) to 7 (lowest PE/weakest base), and explainyour reasoning.
- The following are equivalent ways of asking about the acidity of an H atom: • What is the most acidic H on the molecule? • Which H is associated with the published pKa value? • Which H on the molecule is easiest to remove? • Which H on the molecule takes the least energy to remove? • Which bond to an H is most polarized? • For which H atom is removal least uphill in energy? • Which bond to an H atom, when broken, results in the lowest PE conjugate base? We will often find the last of these questions is easiest to answer. To do this, find all the different Hatoms on the molecule, and draw all possible conjugate bases.Only the lowest-energy one is the “real” conjugate base. Identify this structure, and you have found the most acidic H. Use this strategy to find the most acidic H on each of the following molecules. Note: Each structure hasat least three different kinds of H’s, so draw at least three unique conjugate bases for each.For the molecule with formela GH,ON please draw the Congtitutional isomers withthe properties as ndicated below ALL the cansttutanl isomera molecule of 'this aromatic ring contain Draw Gingle (R) 9tere agenic center any Congttutional isomer with a BO) Draw heteroatom CN oro) in the aromatie ring a congtitutional iscmer that has for the molecule you Show the mogt acidic proton drew in Boxi by drawing the conjuga te base e Draw a Conot tutonal isomer where the mogt acidic proton hao a pka of-5 Draw a congtitutional isomer with aldehyde functional goue dreus in vi) for the molecul you Show the most acidec pro ton by duawing Show the most acid veus In Box y the Conjugate base Oraw a congttutional igomer trat eantain an ester tunctional graffAde ed arrows to show the Arte attack the proton of the acid (breaking the X-H bond * Identify the nucleophile and electrophile ectants but the charge will be on a different molecule.) Circle the conjugate base. charges of any lons OK a) HO, b) кон SH c) NO. ONa HO + Approximate pK, values of Important organic functional groups pk, Protonated Cacborylic alcohol R. -2 5. 10 Phenol 16 Alcohol 25 Alkyne 38 Amine acid 44 Alkene 50 1. H OH R-OH R -H Alkane R. R. он R H ROH Protonated N amine H. H Thiol R-SH
- ety and labl the Lewis acid (electrophile) nd the Lewis base (mcleophile) in the fllowing actions Draw a curved arre tosho the mavement of electrons in the reaction and drew the predact o each reaction 21. What is the relationship betwoen the following two oompounds? A. Constitutional isomers B. Geonetric isomers C. kdentical compounds D. Different compounds 22. What is the relationship between the following two compounds? A. Constitutional isomers B. Geometric isomers C. Identical compounds D. Different compounds 23. Which pair of the following compounds are constitutional isomers? IV A. I and II B. Il and III C.l and IV D. I and IVWhich of the following compounds is the stronger base? Explain. or NH3 is a v base than NCI3. This is due to the difference in the electron withdrawing strength of Cl compared with H. v is more electronegative than and will v more electron density v the nitrogen than Thus, the nitrogen atom in NCI3 has a v positive charge than it does in NH3. The v positive charge means that is v difficult to add H* to NCI3 than it is to add H* to NH3. Is the compound Sb(OH)5 likely to be acidic, basic, or neutral in water? Justify your answer. Phosphorus and arsenic form acids of the form X(OH)n, so one would predict that antimony would be similar as it is in the same family. Based in the number of OH groups present, it should be However, antimony hydroxides are not stable and form oxides which are known to be amphoteric. Thus, Sb(OH)6 is in fact more likely to beSelect (highlight) the most acidic atom of the compound, and um topic H₂C OH
- Draw the products of the following proton transfer reaction. Show all unshared valence electron pairs in your structures. OH HSO draw structure ... draw structure conjugate acid conjugate base t.2. Which structure is the stronger acid, A or B? Explain your answer. F Br ARank the following ions in order of increasing basicity. a. CH,ČH2, CH,0", CH,ÑH c. CH;CO0", CH3CH,O", CICH,COO b. CH", HO", Br d. -C=C", -CH,CH,. -CH=CH