4. Given A vehicle changes velocity from 80.0 km/hr to 20.0 km/hr in 6.00 seconds. Required: Find the uniform acceleration in ft/s2. Be sure to note the sign/direction (+ or -).
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- 4. A particle start from rest and moves in straight line with an acceleration of a- (2t-6) m/s, where t is in seconds. What is the particles velocity when t-és (V(6) - Om/s ), and what is its position when t- 11s?(80.7 m)2. The velocity of a particle moving along a straight line is ve v=t? + 2t m/s, where t is in seconds. If its position s-0 when t-0, determine its acceleration and position when t=4s.4. A motorist covers a displacement of -70.0 km for a period 7.00 minutes. What is his average velocity in m/s?
- 2. An airplane travels 280 m down the runway before taking off. If it starts from rest, moves withconstant acceleration, and becomes airborne in 8.00 s, what is its speed, in m/s, when it takesoff?2. A particle has an initial speed of 44 ft/s. If it experiences a deceleration of a = 31 -8 ft/s, where t is in seconds, determine its velocity, after it has traveled 15 ft. Also, how much time does this take?3. A race car's velocity increases from 4m/s to 36 m/s over a 4.0 s interval. (a) What is its acceleration? (Ans 8m/s? ). (b)The same car now slows down from 36 m/s to 15m/s over 3.0s. What is its acceleration? (Ans -7m/ s).
- 5. A car moves in a straight line such that for a short time its velocity is defined by v ( 3r + 2t m/s, where t is is seconds. Determine the distance travelled when t-3 sec (36m). Determine the acceleration when t-3 s ( 20 m/s)1. The velocity of a particle moving along a straight line is v = t³ + 3t m/s, where t is in seconds. If its position s=0. when t=0, determine its acceleration and position when t=3 seconds.3. The acceleration of a particle traveling along a straight line may be described by the equation a = (0.02e) , where t is in seconds. At t = 0, v = 0 and s = 0. Calculate the 82 velocity and acceleration of the particle at s = 4m.
- 6. The position of a particle along a straight line is given by s = (1.5r - 13.52 + 22.5t) ft, where t is in seconds. Determine the position of the particle when t = 6 s and the total distance it travels during the 6- s time interval. Hint: Plot the path to determine the total distance traveled. Ans. s=6s = -27.0 ft ; Stot = 10.5 + 48.0+ 10.5 69.0 ft 7. A particle moves along a straight line such that its position is defined by s = ( - 6t + 5) m. Determine2. A particle moves in a straight line according to the law s = t¹ - 50t where s is in m and t in seconds. When t=6 seconds, compute the velocity. Find the average velocity during the 4th second.3. A squirrel running at constant acceleration between two points 60.0 m apart in 4.00 seconds. It speed as it passes the 2nd point is 17.0 m/s. a) What is the speed at the first point. b) find acceleration