#4 The proof of converse of Tythagorean Theorem с F 7 b J a B Begin with DABC where we absume 2 Db² = a²+c². With center A and radius Ac, construct a circle. Extend AB in bothe directions E So the diameter meets the circle at D and I Next extend CB to I and draws Cs, AE, and FE. a) Prove I BCD ~ A BFE 5) Use part (a) to conclude FB/BE = CB/B0 and then prove that BE = a c) Grove ABC = AABE d) Prove the converse of Pythagorean

Elementary Geometry for College Students
6th Edition
ISBN:9781285195698
Author:Daniel C. Alexander, Geralyn M. Koeberlein
Publisher:Daniel C. Alexander, Geralyn M. Koeberlein
Chapter6: Circles
Section6.3: Line And Segment Relationships In The Circle
Problem 39E: The center of a circle of radius 2 inches is at a distance of 10 inches from the center of a circle...
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#4
Theorem
F
The proof of converse
F
b
J
converse of Pythagorean
a
B
Begin with DABC
where we absume
b² = 2² +c² With
D b² = a
center A and radius
Ac, construct a circle.
Extend AB in both directions
E
So the diameter meets the circle at D and I
Next extend CB to I and draws ed AE,
and FE
/
a) Prove I BCD ~ ABFE
b) use part (a) to conclude FB/BE = CB/B0
and then prove that BE = a
c) Prove > ABC = AABE
d) Prove the converse of Pythagorean
Theorem by showing now that ABC is
right
Transcribed Image Text:#4 Theorem F The proof of converse F b J converse of Pythagorean a B Begin with DABC where we absume b² = 2² +c² With D b² = a center A and radius Ac, construct a circle. Extend AB in both directions E So the diameter meets the circle at D and I Next extend CB to I and draws ed AE, and FE / a) Prove I BCD ~ ABFE b) use part (a) to conclude FB/BE = CB/B0 and then prove that BE = a c) Prove > ABC = AABE d) Prove the converse of Pythagorean Theorem by showing now that ABC is right
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