4) Early study results show that 80% of customers are willing to pay an extra dollars on their purchase to a local charity. If the margin of error is 0.012 at 95% confidence, find how many customers are surveyed.
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- 1. The manager at Bell's Gym wants to know the proportion of members who use the Cardio Machines. A sample of 260 members showed that 40 of them use cardio machines. Calculate a 97% confidence interval for the proportion of members who use the cardio machines.OA USA Today/CNN/Gallup survey of 365 working parents found 195 who said they spend too little time with their children because of work commitments. a. What is the polnt estimate of the proportion of the population of working parents who feel they spend too little time with their children because of work commitments? (to 4 decimals) b. At 95% confidence, what is the margin of error? (to 4 decimals) c. What is the 05% confidence interval estimate of the population proportion of working parents who feel they spend too little time with their children because of work commitments (to 4 decimals)?Fewer young people are driving. In 1995, 63.9% of people under 20 years old who were eligible had a driver's license. Bloomberg reported that percentage had dropped to 41.7% in 2016. Suppose these results are based on a random sample of 1,200 people under 20 years old who were eligible to have a driver's license in 1995 and again in 2016. a. At 95% confidence, what is the margin of error and the interval estimate of the number of eligible people under 20 years old who had a driver's license in 1995? Margin of error (to four decimal places) Interval estimate to (to four decimal places) b. At 95% confidence, what is the margin of error and the interval estimate of the number of eligible people under 20 years old who had a driver's license in 2016? Margin of error = (to four decimal places) Interval estimate = to (to four decimal places) c. Is the margin of error the same in parts (a) and (b)? - Select your answer v Why, or why not?
- K The first statistics exam had a mean of 71 and a standard deviation of 15 points; the second had a mean of 82 and a standard deviation of 5 points. Anna scored a 84 on both tests. Megan scored 94 on the first exam and 74 on the second. They both totaled 168 points on the two exams, but Anna claims that her total is better. Explain. The total of Anna's z-scores is, which is greater than Megantotal of (Round to one decimal place as needed.)Question: In a survey of buying habits, 400 women shoppers are chosen at random in super market 'A' located in a certain section of the city. Their average weekly food expenditure is dollar 250 with a standard deviation of Dollar 40. For 400 women shoppers chosen at random in super market 'B' in another section of the city, the average weekly food expenditure is Dollar 220 with a standard deviation of Dollar 55. Test at 1% level of significance whether the average weekly food expenditure of the two populations of shoppers are equal.4.43 A firm wishes to estimate the mean number of operating hours of a particular type of lightbulb within 10 operating hours (plus or minus) and with 95% confidence. On the basis of previous knowledge with this type of lightbulb, the firm knows o = 30 h. How large a sample would the firm take? Ans. 35
- 18 We can make a confidence interval more precise (narrower) by, a increasing the sample size. b reducing the confidence level. c increasing the confidence level. d both (a) and (b) are correct.Pop. Mean Stand. Dev. Sample size 1 73.00 10.00 6.00 14 2 62.50 8 1.Independent random samples are selected from two populations. Below are selected summary statistics. (a) Construct the 95% confidence interval for μx-µY. (b) Obtain the P-value for the alternative µx =µY.Question: In a certain factory there are two independent processes manufacturing the same item. The average weight in a sample of 250 items produced from one process is found to be 120 ozs. with a standard deviation of 12 ozs. while the corresponding figures in a sample of 400 items from the other process are 124 and 14. Obtain the standard error of difference between the two sample means. Is this difference significant ? Also find the 99% confidence limits for the difference in the average weights of items produced by the two processes respectively.
- A market researcher states that she has 90% confidence that the mean monthly sales of a product are between $190,000 and $220,000. Explain the meaning of this statement. Choose the correct answer below. O A. If all possible samples of the same size, n= 100, are taken, 90% of those samples will result in a 90% confidence interval that includes the true population mean. Therefore, she is 90% confident that this sample is one that does correctly estimate the mean. O B. A 90% confidence interval contains 90% of the possible sample means. Therefore, she is 90% confident that the interval contains the true population mean. OC. Ifa month was selected, there would be a 90% probability that the mean monthly sales value was within the confidence interval that the researcher found, so the researcher is 90% confident that the true population mean of monthly sales is within the interval. O D. A 90% confidence interval contains 90% of all monthly sales values in the population, so she is 90%…Show your work A stenographer claims that she can take dictation at the rate of 120 words per minute. Can we reject her claim on the basis of 100 trials in which she demonstrates a mean of 116 words with a standard deviation of 15 words? Use 5 per cent level of significance.The level of significance O can be any value between -1.96 to 1.96 can be any positive value can be any value is (1 confidence level) -