4) Borus: Suppose one plate of a parallel-plate capacitor is tilted so it makes a small angle 0 with the other plate, as shown in Fig 24-28. Determine a formula for the capacitance C in terms of A, d, and 0 where A is the area of each plate and 0 is small. Assume the platles are square. [Hint Imagine the capacitor as many infinitesimal capacitors in parallel

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10:13 M J
LTE+
2l 77%|
9:41 P O
80%i
2022-02-17...
4/4
4) Bonus: Suppose one plate of a parallel-plate capacitor is tilted so it makes a small angle 0 with the other plate,
as shown in Fig. 24–28. Determine a formula for the capacitance C in terms of A, d, and 0 where A is the area of
each plate and O is small. Assume the plates are square. [Hint: Imagine the capacitor as many infinitesimal
capacitors in parallel]
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FILTERS
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Transcribed Image Text:10:13 M J LTE+ 2l 77%| 9:41 P O 80%i 2022-02-17... 4/4 4) Bonus: Suppose one plate of a parallel-plate capacitor is tilted so it makes a small angle 0 with the other plate, as shown in Fig. 24–28. Determine a formula for the capacitance C in terms of A, d, and 0 where A is the area of each plate and O is small. Assume the plates are square. [Hint: Imagine the capacitor as many infinitesimal capacitors in parallel] EDIT FILTERS FORMAT
Expert Solution
Step 1

Let the length of the plate be c. The area of the square plate is A=c2.

Consider a small length segment dx on the plate of the capacitor 'x' distance apart from its bottom. 

Advanced Physics homework question answer, step 1, image 1

θ=ArcRadiusArc=θx

The capacitance of the finite small capacitor can be expressed as : 

dC=ε0dAd'=ε0cdxd+xθ

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