4-12. Find the force (magnitude and direction) exerted on the curved surface of the com- pressed air tank shown in Figure 4.47. The tank is 5 m long.
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- Find the internal force systems acting on sections 1 and 2.A man weighs 170 lb on the surface of the earth. Compute his weight in an airplane flying at an elevation of 28 000 ft.Find box for the given Plane, where by =120m, d=25m, bz=25m, d2=100m, b3=80m & d3=25 m (Enter only the values in the boxes by referring the unit given in brackets. Also upload your hand written answers in the link provided) b2 dz di bị The value of X= (unit in m) The value of Y= (unit in m) The moment of inertia for sec 1 = lyyi = (unit in m) The moment of inertia for sec 2 = lyy2 = (unit in m4) The moment of inertia for sec 3 = lyya = (unit in m4) The moment of inertia of the given plate = lyy = (unit in m)
- Equilibrium of Concurrent Force System. The piston of a reciprocating engine exerts a force of 175 kN on the crosshead when the crank is 45° (angle B) past TDC. If the stroke of the piston is 800 mm and the length of the connecting rod is 1.80 m, find the guide force and the force in the connecting rod. Hint: 1=½ stroke; Angle o may be solved using Sine Law in AACO. K= Compressive Force in the connecting Rod E= Piston Effort 70 120 F, = Guide Force Fig. P-1 Fig. P-2 a Tools: EF cos0=0; F sin .=0. R = Ev)* + (E#): ; R 771 =- : tane = sin A sin B sin CPS2-5 Three forces are acting on the problem. List all of the simplifications that can be used in the problem. What is the simplest problem? F₂ 45° RLatch Gate 4ft Latches Water 3.6ft 8.0ft- Hinge Find the magnitude of the pressure force acting on the gate shown in the figure and then calculate its torque around the joint.
- the top view of a door that is 2.4m from the hinges.two equal forces with equal magnitude are applied to the door. -what is the equation used to calculate the torque? -determine the magnitude of torque at point p -third force is acted at position P,so the resultant torque on the door equals zero.what is the possible direction?Figure is a simplified sketch of the mecha- nism used to raise the bucket of a bulldozer. The bucket and its contents weigh 10 kN and have a center of gravity at H. Arm ABCD has a weight of 2 kN and a center of grav- ity at B; arm DEFG has a weight of 1 kN and a center of gravity at E. The weight of the hydraulic cylinders can be ignored. Calculate the force in the horizontal cylinders CJ and El and all forces acting on arm DEFG for the position shown. 30°1, 30° 0.6 m 0.9 m 0.6 m 0.9 m 0.6 m 0.9 m 0.3 mIn Figure 2, solve for the force which will act on the glass window and locate the center of pressure.
- A uniform ladder 8 meters long and weighing 350 N rest against a smooth vertical wall at an angle of 30 to the wall. A 700-N man stands 6 meters up from the bottom of the ladder. Find the horizontal force necessary at the base to keep the ladder from slipping Show the Figure/FBD, given and the formula usedQ3/ A shaft has three eccentric of mass 1 kg cach. The central plane of the eccentrics is 50 mm apart. The distances of the centers from the axis of rotation are 20, 30 and 20 mm and their angular positions are 120° apart. If the shaft is balanced by adding two masses at a radius of 70 mm and at a distance 100 mm from the central plane of the middle eccentric, find the amount of the masses and their angular positions.20 deg. Q3: Explane in which case Fa has a maximum Value & minimum Value in Pulling the car shown in Fig 20