3. The Ecell for agalvanic cell composed of a Li electrode and an unknown electrode was found to be 2.91 volts. Use the Standard Reduction Potential table to determine the identity of the unknown electrode. Show work. Half-Reaction Ag* (aq) + 1e Cu²+ (aq) + 2e Fe³+ (aq) + 3e Ag(s) Cu(s) Fe(s) Zn²+ (aq) + 2e Zn(s) Sn²+ (aq) + 2e Sn(s) Cd2+ (aq) + 2e Cd(s) Mg²+ (aq) + 2e → Mg(s) Ereg(Volts) -0.80 -0.34 -0.04 -0.76 -0.14 -0.40 -2.37
3. The Ecell for agalvanic cell composed of a Li electrode and an unknown electrode was found to be 2.91 volts. Use the Standard Reduction Potential table to determine the identity of the unknown electrode. Show work. Half-Reaction Ag* (aq) + 1e Cu²+ (aq) + 2e Fe³+ (aq) + 3e Ag(s) Cu(s) Fe(s) Zn²+ (aq) + 2e Zn(s) Sn²+ (aq) + 2e Sn(s) Cd2+ (aq) + 2e Cd(s) Mg²+ (aq) + 2e → Mg(s) Ereg(Volts) -0.80 -0.34 -0.04 -0.76 -0.14 -0.40 -2.37
Chemistry: An Atoms First Approach
2nd Edition
ISBN:9781305079243
Author:Steven S. Zumdahl, Susan A. Zumdahl
Publisher:Steven S. Zumdahl, Susan A. Zumdahl
Chapter17: Electrochemistry
Section: Chapter Questions
Problem 160MP
Related questions
Question
![3. The Eel fora galvanic cell composed of a Li electrode and an unknown electrode was found to be
2.91 volts. Use the Standard Reduction Potential table to determine the identity of the unknown
electrode. Show work.
Ered (Volts)
-0.80
-0.34
-0.04
-0.76
-0.14
-0.40
-2.37
Half-Reaction
Ag (aq) + 1e → Ag(s)
Cu²+ (aq) + 2e > Cu(s)
Fe (aq) + 3e > Fe(s)
Zn²+ (aq)
Sn²+ (aq) + 2e
+2e → Zn(s)
Sn(s)
Cd²+ (aq)
+ 2e*
Cd(s)
Mg²+ (aq) + 2e
Mg(s)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fafc721bf-9893-4a4a-88d1-87e8133f42be%2Fec7717b4-de83-4ebc-b2cd-1419bb610b54%2F7ezlvxb_processed.png&w=3840&q=75)
Transcribed Image Text:3. The Eel fora galvanic cell composed of a Li electrode and an unknown electrode was found to be
2.91 volts. Use the Standard Reduction Potential table to determine the identity of the unknown
electrode. Show work.
Ered (Volts)
-0.80
-0.34
-0.04
-0.76
-0.14
-0.40
-2.37
Half-Reaction
Ag (aq) + 1e → Ag(s)
Cu²+ (aq) + 2e > Cu(s)
Fe (aq) + 3e > Fe(s)
Zn²+ (aq)
Sn²+ (aq) + 2e
+2e → Zn(s)
Sn(s)
Cd²+ (aq)
+ 2e*
Cd(s)
Mg²+ (aq) + 2e
Mg(s)
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