3. Complete the function count_digits. This function takes one parameter - a string (s). It should return thenumber of digits in s. For example, if s is "25 or 6 to 4 is a song by Chicago" then count_digits shouldreturn 4. count_digits should not print the result- it should return it. Do not change anything outsidecount_digits.Save & RunLoad HistoryShow CodeLens1 def count_digits(s):2''Returns the number of digits in s''"3pass#Hint: make a string of digits to use#in checking whether each character#is a digit. And use the accumulator#pattern46.78.9 user_string10 num_digits11 print("There are", num_digits, "digits in", user_string)input("Please enter a string: ")count_digits(user_string)12 4. Complete the function show_upper. This function takes one parameter - a string (s). It should return astring made up of all the upper-case characters in s. For example, if s is "aBdDEfgHijK" then show_uppershould return “BDEHK". It should return the upper-case string - not print it. Do not change anythingoutside show_upper.Save & RunLoad HistoryShow CodeLens1 def show_upper(s):'''Returns the upper case characters from s''"2pass45 user_string6 upper_chars7 print(upper_chars)input("Please enter a string: ")show_upper(user_string)8.

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3. Complete the function count_digits. This function takes one parameter - a string (s). It should return the number of digits in s. For example, if s is "25 or 6 to 4 is a song by Chicago" then count_digits should return 4. count_digits should not print the result- it should return it. Do not change anything outside count_digits. Save & Run Load History Show CodeLens 1 def count_digits(s): '''Returns the number of digits in s''' 2 pass #Hint: make a string of digits to use #in checking whether each character #is a digit. And use the accumulator #pattern 4 7 9 user_string = input("Please enter a string: ") 10 num_digits 11 print("There are", num_digits, "digits in", user_string) count_digits(user_string) %3D 12

3. Complete the function count_digits. This function takes one parameter - a string (s). It should return the number of digits in s. For example, if s is "25 or 6 to 4 is a song by Chicago" then count_digits should return 4. count_digits should not print the result- it should return it. Do not change anything outside count_digits. Save & Run Load History Show CodeLens 1 def count_digits(s): '''Returns the number of digits in s''' 2 pass #Hint: make a string of digits to use #in checking whether each character #is a digit. And use the accumulator #pattern 4 7 9 user_string = input("Please enter a string: ") 10 num_digits 11 print("There are", num_digits, "digits in", user_string) count_digits(user_string) %3D 12

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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Topics: User-defined functions, list, string, docstringProblem Statement: This program finds the unique letters from a given string and printsthe unique letters and their count. For example: word ‘LITTLE’ has ‘L’, ‘I’, ‘T’, ‘E’ are theunique letters.Lab Scenario:The program repeats until hits ‘n’. The program takes a user input of a string. The programfinds the unique letters in the string, add them in a list and displays the list and their count.Consider the following important points:1) You need to design a user-defined function named count_unique_letters whichtakes user word as parameter and returns the list of unique letters calledunique_letters in the given word.a. Hint: Iterate over each letter in user word, check if the letter is in the list, if notadd it to the list, otherwise continue to the next letter. A ‘in’ keyword can helpto determine if a character in the unique_letters list.b. You need to write a simple docstring for this function.2) Your program must have a main()…
Complete the rotate_text() function that takes 2 parameters, a string data and an integer n. If n is positive, then the function will shift all the characters in data forward by n positions, with characters at the end of the string being moved to the start of the string. If n is 0 then the text remains the same. For example: rotate_text('abcde', rotate_text('abcde', rotate_text('abcde', 1) would return the string 'eabcd' 3) would return the string 'cdeab' 5) would return the string 'abcde' rotate_text('abcde', 6) would return the string 'eabcd' ... and so on. If n is negative, then the function will shift the characters in data backward by n positions, with characters at the start of the string being moved to the end of the string. For example: rotate text('abcde', -1) would return the string 'bcdea'
Complete the check_strings_same_start(word1, word2) function which is passed two string parameters. The function returns True if the two parameter strings start with the same character and only one (not both) of the parameter strings has an even number of characters (including any space characters), otherwise the function returns False. For example: Test Result result = check_strings_same_start("blue", "bag") True print(result) print(check_strings_same_start("babyproofing", "baby")) False print(check_strings_same_start("check", "fact")) False
Task 2 Get Binary 1: Implement the get_bin_1 function as directed in the comment above the function. If the directions are unclear, run the code, and look at the expected answer for a few inputs. In order to be able to compare your solution to the answer, you cannot simply print out the binary directly to the console. Instead, you have been provided with a very rudimentary stringbuilder implementation that allows you to build a string one character at a time, without the ability to erase. There are comments at the top of the code explaining how to use the stringbuilder, however you could also see how it is being used in task_2_check. Note: if you create a stringbuilder and append ‘a’, ‘b’, then ‘c’, the resulting string will be “abc” when printed. You are free to read through the stringbuilder implementation, but it is quite complicated in order to make it easy to use. As specified in the comment, you may not use division (/) or mod (%) to implement this function (as the check…
Complete the Funnyville High School registration program where user is prompted for her full name and the program generates email id and temporary password. Sample run: generate_EmailID: This function takes two arguments: the user’s first name and last name and creates and returns the email id as a string by using these rules: The email id is all lower case. email id is of the form “last.first@fhs.edu”. e.g. For "John Doe" it will be "doe.john@fhs.edu". See sample runs above. generate_Password: This function takes two arguments: the user’s first name and last name and generates and returns a temporary password as a string by using these rules. Assume that user's first and last names have at least 2 letters. The temporary password starts with the first 2 letters of the first name, made lower case. followed by a number which is the sum of the lengths of the first and last name (For example this number will be 7 for "John Doe" since length of "John" is 4 and length of "Doe" is…
Write the convert_word code. convert_word is known as a function, which we will cover more in depth later. You are automatically given a parameter called word, which is a string that contains a single word. The return conv is how you will send data out of your function. The conv is a variable that hasn't been created yet, but it will be a string containing the converted hey. For example, if word="hey", then conv will be "heey". You are responsible for creating the variable conv, as the template has NOT done that for you. You need to use an if statement to see if the word starts with "he" and ends with "y". Since you don't know how many e's might be between the he and y, you have to do some math here. Recall that you can get the length of a string by using len(word) in the code above. You also know that h and y will be included. so, len(word) - 2 will be the number of e's in between the h and y. Create a string that contains the number of e's. This will be your conv variable. I would…
PYTHON Complete the function below, which takes two arguments: data: a list of tweets search_words: a list of search phrases The function should, for each tweet in data, check whether that tweet uses any of the words in the list search_words. If it does, we keep the tweet. If it does not, we ignore the tweet. data = ['ZOOM earnings for Q1 are up 5%', 'Subscriptions at ZOOM have risen to all-time highs, boosting sales', "Got a new Mazda, ZOOM ZOOM Y'ALL!", 'I hate getting up at 8am FOR A STUPID ZOOM MEETING', 'ZOOM execs hint at a decline in earnings following a capital expansion program'] Hint: Consider the example_function below. It takes a list of numbers in numbers and keeps only those that appear in search_numbers. def example_function(numbers, search_numbers): keep = [] for number in numbers: if number in search_numbers(): keep.append(number) return keep def search_words(data, search_words):
Complete the convert() function that casts the parameter from a float to an integer and returns the result.Note that the returned value of the convert() function is printed. Ex: If the float value is 19.9, then the output is: 19 Ex: If the float value is 3.1, then the output is: 3 this is what i have def largest_number(num1, num2, num3): if(num1 > num2 and num1 > num3): return num1 elif(num2 > num3): return num2 else: return num3 def smallest_number(num1, num2, num3): if(num1 < num2 and num1 < num3): return num1 elif(num2 < num3): return num2 else: return num3 if __name__ == '__main__': n1 = float(input()) n2 = float(input()) n3 = float(input()) print("largest:",largest_number(n1,n2,n3)) print("smallest:",smallest_number(n1,n2,n3)) it says Test convert() with random float value test_passed function missing Traceback (most recent call last): File "main.py", line 18, in <module> n1 = float(input()) EOFError: EOF when reading a line Your output Your…
For this problem set, you will submit java file named Homework.java Return Growing NumList This function will be given a single number, it should return a list of strings of numbers. Each string in the list will only contain a single number repeated an arbitrary amount of times. The number each string will contain will be equal to the current string's index+1. The number in the string should be repeated the same number of times as the string's index+1. Each number in the string should be separated by a space. This list should stop when its size equals the max number specified. Signature: public static ArrayList<String> returnGrowingNumList(int max) Example: INPUT: 3OUTPUT: [1, 2 2, 3 3 3] INPUT: 6OUTPUT: [1, 2 2, 3 3 3, 4 4 4 4, 5 5 5 5 5, 6 6 6 6 6 6]
Brussel's choice def brussels_choice_step(n, mink, maxk): This problem is adapted from another jovial video "The Brussel's Choice" of Numberphile (a site so British that you just know there has to be a Trevor and a Colin somewhere in there) whose first five minutes you should watch to get an idea of what is going on. This function should compute and return the list of all numbers that the positive integer n can be converted to by treating it as a string and replacing some substring m of its digits with the new substring of either 2*m or m/2, the latter substitution allowed only when m is even so that dividing it by two produces an integer. This function should return the list of numbers that can be produced from n in a single step. To keep the results more manageable, we also impose an additional constraint that the number of digits in the chosen substring m must be between mink and maxk, inclusive. The returned list must contain the numbers in ascending sorted order.
Create a function that takes a string and returns a string with its letters in alphabetical order. Examples alphabet_soup("hello") - "ehllo" alphabet_soup("edabit") - "abdeit" alphabet_soup("hacker") - "acehkr" alphabet_soup ("geek") - "eegk" alphabet_soup("javascript") "aacijprstv"
get_nth_word_from_string(s, n): This function takes a string s and a non-negative integer n as input. The string s may contain substrings of text separated by commas. The function should return the n’th comma-separated substring. We will start counting at 0, so if n=0, then the first substring should be returned (i.e., everything before the first comma, if there is such a comma); if n=1, then the second substring should be returned (i.e., everything between the first comma and second comma, if there is such a comma); and so on. If there is no n’th substring in s, then the empty string should be returned. Note: You may use the string count method in this function. Note: If a space follows a comma, do not include the space as part of the substring to be returned. >>> get_nth_word_from_string("dreary, pondered, weak, weary", 0) 'dreary'