27.a) Two parallel shafts are to be connected by spur gearing. The axes of shafts are to be at 560 mm apart as nearly as possible. If driver shaft rotates at 100 rpm and the driven shaft rotates at 430 rpm, find the number of teeth on each gear, if the module is to be 2 mm. Determine the exact distance between the two shafts.

Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
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27.a) Two parallel shafts are to be connected by spur gearing. The axes of shafts are to be at 560 mm apart as nearly as possible. If driver
shaft rotates at 100 rpm and the driven shaft rotates at 430 rpm, find the number of teeth on each gear, if the module is to be 2 mm.
Determine the exact distance between the two shafts.
27.b) A cam with roller follower moves outward stroke with simple harmonic motion and return stroke with uniform acceleration and
retardation. Determine the maximum velocity and acceleration of the follower, during its outward stroke and return stroke, if cam rotates
at 260 rpm. CAM lift is 44 mm during outward stroke 130.23255813953° of CAM rotation with simple harmonic motion. Dwell for the
next 30 degrees, During the return stroke 40° of cam rotation the follower returns to its original position with uniform acceleration and
retardation.
27.a) No of Teeth on driver gear =
27.a) No of Teeth on driven gear=,
27.a) Exact distance between two shafts=.
mm.
27.b) Max velocity during outward stroke =
m/sec
27.b) Max Velocity during return stroke =
m/sec.
27.b) Max Acceleration during outward stroke =
m/sec?
27.b) Max Acceleration during return stroke =
m/sec?
Transcribed Image Text:27.a) Two parallel shafts are to be connected by spur gearing. The axes of shafts are to be at 560 mm apart as nearly as possible. If driver shaft rotates at 100 rpm and the driven shaft rotates at 430 rpm, find the number of teeth on each gear, if the module is to be 2 mm. Determine the exact distance between the two shafts. 27.b) A cam with roller follower moves outward stroke with simple harmonic motion and return stroke with uniform acceleration and retardation. Determine the maximum velocity and acceleration of the follower, during its outward stroke and return stroke, if cam rotates at 260 rpm. CAM lift is 44 mm during outward stroke 130.23255813953° of CAM rotation with simple harmonic motion. Dwell for the next 30 degrees, During the return stroke 40° of cam rotation the follower returns to its original position with uniform acceleration and retardation. 27.a) No of Teeth on driver gear = 27.a) No of Teeth on driven gear=, 27.a) Exact distance between two shafts=. mm. 27.b) Max velocity during outward stroke = m/sec 27.b) Max Velocity during return stroke = m/sec. 27.b) Max Acceleration during outward stroke = m/sec? 27.b) Max Acceleration during return stroke = m/sec?
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