2.) Striking a match stick on the matchbox involves the reaction of potassium chlorate and red phosphorus with the following equation: 10 KCIO3 (s) + 3 P4 (s) ---> 3 P4O10 (s) + 10 KCI (s) (A) How much reactant (KCIO3) will be needed to produce 105.8 g of P4O10? (B) How much reactant (P4) will be needed to produce 105. g of P4010? Molar Masses: 1 mole of KCIO3 = 122.55 grams of KCIO3 1 mole of P4 = 123.88 grams of P4 1 mole of P4O10 = 283.88 grams of P4010 Ratio: 10 mole of KCIO3 = 3 mole of P4010 3 mole of P4 = 3 mole of P4010

Introduction to General, Organic and Biochemistry
11th Edition
ISBN:9781285869759
Author:Frederick A. Bettelheim, William H. Brown, Mary K. Campbell, Shawn O. Farrell, Omar Torres
Publisher:Frederick A. Bettelheim, William H. Brown, Mary K. Campbell, Shawn O. Farrell, Omar Torres
Chapter4: Chemical Reactions
Section: Chapter Questions
Problem 4.93P: 4-93 Ammonia is prepared industrially by the reaction of nitrogen and hydrogen according to the...
icon
Related questions
Question
2.) Striking a match stick on the matchbox involves the
reaction of potassium chlorate and red phosphorus with
the following equation:
10 KCIO3 (s) +3 Р4(s) ---> 3 РАО10 (s) + 1О КСІ (5)
(A) How much reactant (KCIO3) will be needed to produce
105.8 g of P4010?
(B) How much reactant (P4) will be needed to produce 105.8
g of P4010?
Molar Masses:
1 mole of KCIO3 = 122.55 grams of KCIO3
%3D
1 mole of P4 = 123.88 grams of P4
%3D
1 mole of P4010 = 283.88 grams of P4010
Ratio:
10 mole of KCIO3 = 3 mole of P4010
3 mole of P4 = 3 mole of P4O10
Transcribed Image Text:2.) Striking a match stick on the matchbox involves the reaction of potassium chlorate and red phosphorus with the following equation: 10 KCIO3 (s) +3 Р4(s) ---> 3 РАО10 (s) + 1О КСІ (5) (A) How much reactant (KCIO3) will be needed to produce 105.8 g of P4010? (B) How much reactant (P4) will be needed to produce 105.8 g of P4010? Molar Masses: 1 mole of KCIO3 = 122.55 grams of KCIO3 %3D 1 mole of P4 = 123.88 grams of P4 %3D 1 mole of P4010 = 283.88 grams of P4010 Ratio: 10 mole of KCIO3 = 3 mole of P4010 3 mole of P4 = 3 mole of P4O10
Expert Solution
trending now

Trending now

This is a popular solution!

steps

Step by step

Solved in 6 steps

Blurred answer
Knowledge Booster
Mole Concept
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.
Similar questions
Recommended textbooks for you
Introduction to General, Organic and Biochemistry
Introduction to General, Organic and Biochemistry
Chemistry
ISBN:
9781285869759
Author:
Frederick A. Bettelheim, William H. Brown, Mary K. Campbell, Shawn O. Farrell, Omar Torres
Publisher:
Cengage Learning
Chemistry for Engineering Students
Chemistry for Engineering Students
Chemistry
ISBN:
9781337398909
Author:
Lawrence S. Brown, Tom Holme
Publisher:
Cengage Learning
Chemistry for Engineering Students
Chemistry for Engineering Students
Chemistry
ISBN:
9781285199023
Author:
Lawrence S. Brown, Tom Holme
Publisher:
Cengage Learning
Chemistry: Principles and Practice
Chemistry: Principles and Practice
Chemistry
ISBN:
9780534420123
Author:
Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Publisher:
Cengage Learning
Chemistry & Chemical Reactivity
Chemistry & Chemical Reactivity
Chemistry
ISBN:
9781337399074
Author:
John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Publisher:
Cengage Learning
Chemistry by OpenStax (2015-05-04)
Chemistry by OpenStax (2015-05-04)
Chemistry
ISBN:
9781938168390
Author:
Klaus Theopold, Richard H Langley, Paul Flowers, William R. Robinson, Mark Blaser
Publisher:
OpenStax