2. For the chemical equilibrium below: CH3CH2NH2 + H2O +CH3CH2NH3* + OH Ka = 2.31 x 10-1" a. Write the base dissociation constant expression (Kb). b. Calculate the base dissociation constant (Kb). c. Calculate the hydroxide ion concentration in 0.100 M Ethylamine (CH3CH2NH2) at 25 °C. d. Calculate the hydronium ion concentration in 0.100 M Ethylamine (CH3CH2NH2) acid at 25 °C.

Chemistry: The Molecular Science
5th Edition
ISBN:9781285199047
Author:John W. Moore, Conrad L. Stanitski
Publisher:John W. Moore, Conrad L. Stanitski
Chapter14: Acids And Bases
Section: Chapter Questions
Problem 112QRT
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2. For the chemical equilibrium below:
CH3CH2NH2 + H2O CH3CH2NH3* + OH
Ka = 2.31 x 10-"
a. Write the base dissociation constant expression (Kb).
b. Calculate the base dissociation constant (Kb).
c. Calculate the hydroxide ion concentration in 0.100 M Ethylamine (CH3CH2NH2) at 25 °C.
d. Calculate the hydronium ion concentration in 0.100 M Ethylamine (CH3CH2NH2) acid at 25
°C.
Transcribed Image Text:2. For the chemical equilibrium below: CH3CH2NH2 + H2O CH3CH2NH3* + OH Ka = 2.31 x 10-" a. Write the base dissociation constant expression (Kb). b. Calculate the base dissociation constant (Kb). c. Calculate the hydroxide ion concentration in 0.100 M Ethylamine (CH3CH2NH2) at 25 °C. d. Calculate the hydronium ion concentration in 0.100 M Ethylamine (CH3CH2NH2) acid at 25 °C.
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