-2 2 A = 2 2 -2 4 Step 3: Find a possible basis for the smaller eigenvalue X1. There are infinitely many possibilities but we will restrict ourselves to fill in only either 1 or 0. Answer: a basis for the eigenspace corresponding to the smaller eigenvalue A1 is a d where a= 1 . b= 1 , c= 1 ,d= 1 are all positive integers with no common divisor.

-2 2 A = 2 2 -2 4 Step 3: Find a possible basis for the smaller eigenvalue X1. There are infinitely many possibilities but we will restrict ourselves to fill in only either 1 or 0. Answer: a basis for the eigenspace corresponding to the smaller eigenvalue A1 is a d where a= 1 . b= 1 , c= 1 ,d= 1 are all positive integers with no common divisor.

Elementary Linear Algebra (MindTap Course List)

8th Edition

ISBN:9781305658004

Author:Ron Larson

Publisher:Ron Larson

Chapter7: Eigenvalues And Eigenvectors

Section7.1: Eigenvalues And Eigenvectors

Problem 80E

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