Given the per unit values below determine the L-L, L-G, L-L-G and 3Phase fault at the location shown in the figure. Thepre-fault voltage at the fault location is 16.5kVL-L. and the load current is negligible. The source impedances shown are thesub-transient reactances of the generator. Assume 100MVA base.15kV100 MVA SstoΔ+ Δ.15 kVR 100 MVA+6Zines Zune2 = 138ZLineo=153 238☺ HZ₁ =j15%Z₂=112%Z₁ -17%15/138 KV100 MVAZ₁ = 18%Z₂ = 17%Z. =j5%138/15kV100 MVAZ₁ =18%Z₂ =j7%Z₁ =j5%ⒸZRI=117%ZR2=112%ZRO -10%Z-j0.08 pu The per unit values of positive, negative and zero sequence reactances of a network at fault are 0-08, 0-07 and 0-05respectively. Determine the fault current if fault is line-to-line-to-ground.

Answered: Image /qna-images/answer/46241715-3f12-4675-958e-9a59fcc98df6.jpg

15KV 100 MVA S Z₁ =j15% Z₂=112% Z₁ -17% At + AR Zunes = Zune2=1382 38 ZLineo=1532 138/15KV 15/138 KV 100 MVA Z, -18% Z, -17% Z₁ =15% 100 MVA Z₁ =18% Z₂ =j7% Z₁ =15% 15 kV 100 MVA ZR-17% ZR2=112% ZRO 10% Zj0.08 pu

15KV 100 MVA S Z₁ =j15% Z₂=112% Z₁ -17% At + AR Zunes = Zune2=1382 38 ZLineo=1532 138/15KV 15/138 KV 100 MVA Z, -18% Z, -17% Z₁ =15% 100 MVA Z₁ =18% Z₂ =j7% Z₁ =15% 15 kV 100 MVA ZR-17% ZR2=112% ZRO 10% Zj0.08 pu

Power System Analysis and Design (MindTap Course List)

6th Edition

ISBN:9781305632134

Author:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma

Publisher:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma

Chapter7: Symmetrical Faults

Section: Chapter Questions

Problem 7.2MCQ: Even though the fault current is not symmetrical and not strictly periodic, the rms asymmetrical...

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Question

Given the per unit values below determine the L-L, L-G, L-L-G and 3Phase fault at the location shown in the figure. The
pre-fault voltage at the fault location is 16.5kVL-L. and the load current is negligible. The source impedances shown are the
sub-transient reactances of the generator. Assume 100MVA base.
15kV
100 MVA S
sto
Δ
+ Δ.
15 kV
R 100 MVA
+6
Zines Zune2 = 138
ZLineo=153 2
38
☺ H
Z₁ =j15%
Z₂=112%
Z₁ -17%
15/138 KV
100 MVA
Z₁ = 18%
Z₂ = 17%
Z. =j5%
138/15kV
100 MVA
Z₁ =18%
Z₂ =j7%
Z₁ =j5%
Ⓒ
ZRI=117%
ZR2=112%
ZRO -10%
Z-j0.08 pu

The per unit values of positive, negative and zero sequence reactances of a network at fault are 0-08, 0-07 and 0-05
respectively. Determine the fault current if fault is line-to-line-to-ground.

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