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- A 15-F AC capacitor is connected in series with a 50 resistor. The capacitor has a voltage rating of 600 WVDC. The capacitor and resistor are connected to a 480-V, 60-Hz circuit. Is the voltage rating of the capacitor sufficient for this connection?The waveform displayed on an oscilloscope is as shown in Figure The 'time/cm' switch is set to 0.2 ms/cm, and the 'volts/cm' switch is set to 40 V/cm. Determine the (i) amplitude of waveform Q, (ii) peak to peak value of waveform P, (ii) frequency of waveform P and (iv) phase angle difference between P and Q in Degrees. Upload your Answers steps in the "Final Answer Submission" Link provided in the Moodle. (i) Amplitude of waveform Q = (ii) Peak to peak value of waveform P = (iii) Frequency of waveform P = (iv) Phase angle difference between P and Q in Degrees =The waveform displayed on an oscilloscope is as shown in Figure The 'time/cm' switch is set to 0.2 ms/cm, and the 'volts/cm' switch is set to 30 V/cm. Determine the (1) amplitude of waveform Q, (i) peak to peak value of waveform P, (ii) frequency of waveform P and (iv) phase angle difference between P and Q in Degrees. Upload your Answers steps in the "Final Answer Submission" Link provided in the Moodle. (i) Amplitude of waveform Q = (ii) Peak to peak value of waveform P = (iii) Frequency of waveform P = (iv) Phase angle difference between P and Q in Degrees =
- The waveform displayed on an oscilloscope is as shown in Figure The 'time/cm' switch is set to 2 ms/cm, and the 'volts/cm' switch is set to 1 V/cm. Determine the (i) amplitude of waveform Q (i) peak to peak value of waveform P. (ii)i frquency of waveform P and (iv) phase angle difference between P and Q in Degrees. Upload your Answers steps in the "Final Answer Submission" Link provided in the Moodle. () Amplitude of waveform Q = (ii) Peak to peak value of waveform P = (ii) Frequency of waveform P = (iv) Phase angle difference between P and Q in Degrees =A 5-ohm resistor is connected in series with a 25 micro-farad capacitor. A source voltage of 158 volts, 50 Hz supplies the combination. Determine the following: a. Circulating current b. Voltage across the resistor c. Voltage across the capacitor3-phase transfomer configuration in figure imagen: Ammeter A4 is measuring_______, Ammerter A5 is measuring_____, Ammerter A6 is measuring___, Voltmeter V1 is measuring_____, voltmeter V2 is measuring____, Voltmeter V3 is measuring ______, Voltmeter V4 is measuring_____,Voltmeter V5 is measuring______. A- line voltage B-phase voltage C- meither "a" nor "b" d- both "a" and "b"
- The waveform displayed on an oscilloscope is as shown in Figure The 'time/cm' switch is set to 0.5 ms/cm, and the 'volts/cm' switch is set to 0.2 V/cm. Determine the (i) amplitude of waveform Q, (ii) peak to peak value of waveform P, (iii) frequency of waveform P and (iv) phase angle difference between P and Q in Degrees. Upload your Answers steps in the "Final Answer Submission" Link provided in the Moodle. (i) Amplitude of waveform Q = (ii) Peak to peak value of waveform P = (iii) Frequency of waveform P =Given an oscilloscope input resistance (R2 in Figure 3 b) is 1MegΩ. Find the probe resistance (R1) so that the ratio of the source voltage (Vs) to the oscilloscope input voltage (Vin) is Vs/Vin = 10. R1=?5. For the square voltage waveform displayed on an oscilloscope shown in Figure 2, find (a) its frequency, (b) its peak-to-peak voltage. 100 us Von ecm a) Frequency = 50HZ Voltage=176 V b) Frequency = 41.67kHz Voltage=240 V c) Frequency = 41.67kHz Voltage=176 V