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= 11. Obtain the solution using Integrating Factors Found by Inspection 1. ydx+2(y-x)dy = 0 2. y(x³exy - y)dx + x(y + x³exy)dy = 0 3. 2xy' y(3x²+y²) 4. y(x³y3+2x2 − y)dx + x³ (xy³ - 2)dy = 0; when x = 1, y = 1 5. (2y3x)dx + xdy = 0

= 11. Obtain the solution using Integrating Factors Found by Inspection 1. ydx+2(y-x)dy = 0 2. y(x³exy - y)dx + x(y + x³exy)dy = 0 3. 2xy' y(3x²+y²) 4. y(x³y3+2x2 − y)dx + x³ (xy³ - 2)dy = 0; when x = 1, y = 1 5. (2y3x)dx + xdy = 0

Calculus For The Life Sciences
Calculus For The Life Sciences
2nd Edition
ISBN:9780321964038
Author:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.
Publisher:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.
Chapter11: Differential Equations
Section11.1: Solutions Of Elementary And Separable Differential Equations
Problem 2YT
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= 11. Obtain the solution using Integrating Factors Found by Inspection 1. ydx+2(y-x)dy = 0 2. y(x³exy - y)dx + x(y + x³exy)dy = 0 3. 2xy' y(3x²+y²) 4. y(x³y3+2x2 − y)dx + x³ (xy³ - 2)dy = 0; when x = 1, y = 1 5. (2y3x)dx + xdy = 0
Transcribed Image Text:= 11. Obtain the solution using Integrating Factors Found by Inspection 1. ydx+2(y-x)dy = 0 2. y(x³exy - y)dx + x(y + x³exy)dy = 0 3. 2xy' y(3x²+y²) 4. y(x³y3+2x2 − y)dx + x³ (xy³ - 2)dy = 0; when x = 1, y = 1 5. (2y3x)dx + xdy = 0
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