1007 A compound whose molecular formula is C5H1,0 has the IR spectrum shown. The compound's pK, is >40. 80- Propose a structure for this compound that is consistent with these data. 60- 40- 20- C3H1,0 0누 4500 4000 3500 3000 2500 2000 1500 1000 500 Wavenumbers (cm-1) % Transmittance
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- The mass spectrum and 13C NMR spectrum of a hydrocarbon are shown. Propose a structure for this hydrocarbon, and explain the spectral data.A compound whose molecular formula is C3H202 has the IR spectrum shown. Propose a structure for this compound and estimate its pkg. 100- 80- 60- 40- 20- C3H2O2 4500 4000 3500 3000 2500 2000 1500 1000 500 Wavenumbers (cm-1) % TransmittanceConsider the data for an unknown compound with the molecular formula C,HOz. • IR: 2400–3200 cm¬1, 1700 cm-1, 1630 cm 'H NMR: 8 1.53 (3 H, t, J = 8 Hz); 8 4.32 (2H, q, J = 8 Hz); 8 7.08, & 8.13 (4 H, pair of leaning doublets, J = 10 Hz); 8 10 (1 H, broad, disappears with D,O shake) %3D Deduce the structure for C, H O2- 10 3 Select Draw Rings More Erase C HO of
- 6) The compound with the molecular formula C4H10O was synthesized. It was further analyzed using IR spectroscopy. The spectrum of the compound is illustrated below. Identify the structure of a compound. Justify your answer. Identify as many peaks on its IR spectrum as possible. (5 points) 100 80 60 60 %T 40 20 20 0 4000 R2020-93124TM 3000 2000 1500 1000 400 Wavenumber [cm-1]#3: C₂H13N (peaks: @3.6ppm-singlet, @2.9ppm-septet, @1.2ppm-doublet) - IR shows peaks @3300, 3010, 1606 and 1585cm-¹ 3 7 4H 6 5 300 MHz 'H NMR In CDC3 2.11 4 3 2H 1H 2 1 6H possible structure 0The simulated APT spectrum of a compound with the molecular formula CH₁ Cl is shown. Draw a structure that is consistent with this data. 100 50 0 -50 -100 70 65 Draw the structure. T 60 55 50 45 40 35 30 T 25 20 15 10 -5 Lo
- A compound has the molecular formula: C4H8O2 and gives the following C-13 NMR spectrum. Provide the most likely functional groups for each signal. nmrsim presentation 1 1 C:Bruken Topspin3.5pl7 examdata -170.7658 150 100 d 170.8 (O CH3) ; 60.4 (OCH2); 20.8, 14.1 (2 x C=0) 8170.8 (0 CH₂); 60.4 (OCH₂); 20.8, 14.1 (2 x CH3). 8 170.8 (CH3); 60.4 (C-0); 20.8, 14.1 (2 x OCH₂) 8170.8 (C=0); 60.4 (OCH₂); 20.8, 14.1 (2 x CH3). 8170.8 (C) ; 60.4 (O CH2); 20.8, 14.1 (2 x O CH3) -60.4293 50 -20.7902 -14.1385 [ppm] [+]3. A compound has the following MS & IR spectra. Propose a structure. Relative Intensity Transmitance 100 1.0 6.4 43 3100 nos 3000 147 2500 Mass Spectrum 00 m/z 100 Infrared Spectrum 2000 Wavenumbers (cm-1) ww 120 Y 1500 1135 140 140 Br 1:1 M+2 APR 110 10002. Determine the structure of a compound with a molecular formula of C6H120 and exhibits the following 'H NMR and 1°C NMR spectra. No peaks exchange in D20. | = 6 = 3 200 100 0.0 13 C NMR 1.1 1.0 | = 2 | = 1 %3D 2.6 2.5 2.4 9.0 8.0 7.0 6.0 5.0 4.0 3.0 2.0 1.0 0.0 1 H NMR
- Below is a DEPT-135 spectrum for compound D. Identify a structure for compound D that is consistent with the data in the spectrum. Compound D- DEPT 135 90 70 8 (ppm) CH3 A CH H3C 50 30 10 CH₂CH₂CH-Cl CH3 CH₂CH₂CH₂CH₂-Cl CH3 CH3-C-CH3 Cl% Transmittance 180 90 80 70 60 50 40 30 20 10 0- 4000 5 H 8 (c) Below is a IR, ¹H NMR and ¹³C NMR spectra of an unknown compound. Draw the structure of the compound. Molecular Formula = C9H10O2 ¹H NMR spectrum 7 C-H stretch (aromatic) 160 140 3078 6 2986 C-H stretch (alkyl) 5 C=O stretch 1726 2000 Wavenumbers (cm-1) 2 H 4 ppm 120 100 PPM 3 80 13 2 3 H 60 1117 C-O stretches 1286 1 C NMR Spectrum 0 40 20 12Use the spectral information given below to derive a structural formula for unknown I. Its molecular formula is C8H10. 100 IR Spectrum of Unknown 1 %T 50- 4000 3000 2000 1500 1000 50 Wavenumbers (cm-1) HNMR Spectrum of Unknown I 8 6 5 3 2 1 PPM C13NMR Spectrum of Unknown I 140 120 100 80 PPM 60 40 20