10) F(s) = 11) F(s) = 12) F(s) = 1 S4-45² nπ (s+2)² +n²n² S (s+3)² +1 (21)--1/1 Ans. f(t)=-sinh(2t) Ans. f(t)=e" sin(nt) Ans. f(t)=e³¹(cos(t)-3 sin(t))

Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
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Q/Find the Inverse Laplace
Transform of the following functions
Ans. f()=-sinh(20)--
10) F(s)=-
11) F(s) =
1
S-4s²
(s+2)² +n²r²
12) F(s)=-
15) F(s) =
S
(s+3)² +1
2(e-2s
13) F(s)=-
na
-as
14) F(s) =
s) ==
-e-4²)
S
(e+e-²-3e-³s +e6s)
Ans. f(t)= e sin(not)
Ans. f(t)=e³¹(cos(t)-3 sin(t))
Ans. f(t)=<
f(1) = {²
Ans. f(t)=
Ans. f(t)=
t-a
4
0
t-1
2t-3
6-t
0
2<t<4
elsewhere
t>a
t<a
143
Edited with the trial version of
Foxit Advanced PDF Editor
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1<t <2
2<t <3
3<t<6
elsewhere
Transcribed Image Text:Q/Find the Inverse Laplace Transform of the following functions Ans. f()=-sinh(20)-- 10) F(s)=- 11) F(s) = 1 S-4s² (s+2)² +n²r² 12) F(s)=- 15) F(s) = S (s+3)² +1 2(e-2s 13) F(s)=- na -as 14) F(s) = s) == -e-4²) S (e+e-²-3e-³s +e6s) Ans. f(t)= e sin(not) Ans. f(t)=e³¹(cos(t)-3 sin(t)) Ans. f(t)=< f(1) = {² Ans. f(t)= Ans. f(t)= t-a 4 0 t-1 2t-3 6-t 0 2<t<4 elsewhere t>a t<a 143 Edited with the trial version of Foxit Advanced PDF Editor To remove this notice, visit: www.foxitsoftware.com/shopping 1<t <2 2<t <3 3<t<6 elsewhere
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