TRANSCRIBE THE FOLLOWING TEXT IN DIGITAL FORMAT )e(Let Trigonometric form ofisr cose + r sin oAs such here,4+3 ₁&rcosoqrgin = 3Squaring the two and adding22r²(cos ²0+ sin²0) = (4) ²² + (3) ²2=>7ъв2r = 5Dividing we get,tano = 3= 25->4+314+3iHence, Trigonometric form istan² (²2/7/)=for polar form5 Coso tissino" complex number@?= 5 (cose +istno),4+3;=sewhere @ = tan!a@Ans= tań² (²³/1/)(2)0 = tan¹ (²)

Answered: Image /qna-images/answer/2e3a05ae-825f-4016-9fd4-09598a223f56.jpg

(10) 4+31 & Let Trigonometric form of is rcosc +r sin o As such here, rcos = 4 ring = 3 Squaring the two and adding 2 r²(cos ²0+ sinlo] = (4)² + (3) => r = s = 25 Dividing we get, tano = 3 2/1/4 = 4+31 = Hence, Trigonometric for = tań (²/17) a complex number 5 Coso tissino for polar form is ++3² = 5 (Cosm tisino), tan' (²) where @ = tan¹ 0= tan¹ (3)

(10) 4+31 & Let Trigonometric form of is rcosc +r sin o As such here, rcos = 4 ring = 3 Squaring the two and adding 2 r²(cos ²0+ sinlo] = (4)² + (3) => r = s = 25 Dividing we get, tano = 3 2/1/4 = 4+31 = Hence, Trigonometric for = tań (²/17) a complex number 5 Coso tissino for polar form is ++3² = 5 (Cosm tisino), tan' (²) where @ = tan¹ 0= tan¹ (3)

Algebra & Trigonometry with Analytic Geometry

13th Edition

ISBN:9781133382119

Author:Swokowski

Publisher:Swokowski

Chapter6: The Trigonometric Functions

Section6.3: Trigonometric Functions Of Real Numbers

Problem 21E

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