1. TRANSIT RULE. Given in the accompanying tabulation are theobserved data for a traverse obtained from a transit - tape survey. De-termine the latitudes and departures .of each course and balance thesequantities by employing the transit rule. Tabulate values accordingly.AZIMUTHAZIMUTHCOURSE LENG THCOURSELENGTHFROM NORTHFROM NORTH167°35'263°44'304°51'495.85m5°30'46°02'112°22'ABDE1,020.87mвс1,117.26660.08850.62EFCD855.45FA2. ADJUSTMENT OF LENGTHS AND AZIMUTHS. Given the observedand calculated data in Problem No. I. Determine the adjusted length andadjusted azimuth (reckoned from north) of each course and tabulate valuesaccordingly.

We can adjust the Traverse by 2 methods Transit method Compass method

1. TRANSIT RULE. Given in the accompanying tabulation are the observed data for a traverse obtained from a transit - tape survey. De- termine the latitudes and departures .of each course and balance these quantities by employing the transit rule. Tabulate values accordingly. AZIMUTH FROM NORTH AZIMUTH COURSE LENG TH COURSE LENGTH FROM NORTH 167°35' 263°44' 304°51' 495.85m 5 30' 46°02' 112°22' AB DE 1,020.87m вс 850.62 1,117.26 660.08 EF CD 855.45 FA 2. ADJUSTMENT OF LENGTHS AND AZIMUTHS. Given the observed and calculated data in Problem No. I. Determine the adjusted length and adjusted azimuth (reckoned from north) of each course and tabulate values accordingly.

1. TRANSIT RULE. Given in the accompanying tabulation are the observed data for a traverse obtained from a transit - tape survey. De- termine the latitudes and departures .of each course and balance these quantities by employing the transit rule. Tabulate values accordingly. AZIMUTH FROM NORTH AZIMUTH COURSE LENG TH COURSE LENGTH FROM NORTH 167°35' 263°44' 304°51' 495.85m 5 30' 46°02' 112°22' AB DE 1,020.87m вс 850.62 1,117.26 660.08 EF CD 855.45 FA 2. ADJUSTMENT OF LENGTHS AND AZIMUTHS. Given the observed and calculated data in Problem No. I. Determine the adjusted length and adjusted azimuth (reckoned from north) of each course and tabulate values accordingly.

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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3. AREA BY DPD. In the accompanying tabulations are the adjusted latitudes and adjusted departures of two traverse. By employing the double parallel distance method, determine the area (in sq.m. and ha.) of each traverse. ADJUSTED LATITUDE ADJUSTED DEPARTURE LINE +N -S +E -w AB 420.75 713.84 BC 296.08 693.05 CD 894.37 405.36 DE 501.25 926.54 EF 386.42 695.04 FA 884.53 190.67 Sums +1691.70 F1691.70 181 2.25 1812.25 ADJUSTED LATITUDE ADJUSTED DEPARTURE COURSE +N +E 1-2 299.30 295.58 2-3 338.05 223.56 24.52 245.77 381,36 230.52 4-5 8.05 5-6 463.09 6 - 1 626.11 309. 87 Sums +949.93 -949.93 + 772.96 -772.96
Given in the accompanying tabulation are the observed data for a closed traverse obtained from a survey. a. Compute for the unknown quantities b. Compute the area of the lot using DMD or DPD Method LINE LENGTH (m) AZIMUTH FROM NORTH AB 233.10 122°30' ВС 242.05 85°15' CD 191.50 20°00' DE unknown unknown EF 270.65 254°05' FA 252.38 213°00'
Given in the accompänying tabulation are the observed data for a traverse obtained from a transit tape survey. Balance these quantities by employing the compass rule and answer the following questions. COURSE DISTANCE (m) BEARING ... 1-2 495.85 N5°30'E 2-3 850.62 N46°2'E 3-4 855.45 S67°38'E 4-5 1020.87 S12°25'E 5-6 1117.26 S83°44'W 6-1 660.08 N55°9'W a) Determine linear error of ciosure. Blank 1 b) Relative Precdsion (example: 1/1000.11). Blank 2 C) Adjusted length of course 1-2. Blank 3 d) Adjusted length of course 4-5. Blank 4 e) Adjusted length of course 6-1. Blank 5
From the following traverse notes, compute the corrected distance of line CD using Transit Rule. LINE BEARING DISTANCE LATITUDE DEPARTURE А-В N 15 30' E 60.00 m + 57.81 16.03 В-С S 82 23' E 72.69 9.63 72.04 S 17° 20' E - 42.79 C-D 44.83 13.36 D-E S 70 36' W 56.45 18.75 53.25 E-A N 74 20' W 50.00 + 13.50 48.14
Q1. Calculate departures and latitudes of the following ABCDE traverse. 3 N A 285.40' •N26°10'E E 5 75 25 E 640.45' 647.02' 5306 W N 0°42' W 720.8 203.00 5 15 30¹ W
I. TRANSIT RULE. Given in the accompanying tabulation are the observed data for a traverse obtained from a transit- tape survey. De- termine the latitudes and departures of each course and balance these quantities by employing the transit rule. Tabulate values accordingly. COURSE LENGTH AB BC CD 495.85m 850.62 855.45 AZIMUTH FROM NORTH 5°30' 46 02' 112°22' COURSE LENGTH 1,020.87m 1,117.26 660.08 DE EF FA AZIMUTH FROM NORTH 167°35' 263 44' 304°51' 2. ADJUSTMENT OF LENGTHS AND AZIMUTHS. Given the observed and calculated data in Problem No. I. Determine the adjusted length and adjusted azimuth (reckoned from north) of each course and tabulate values accordingly.
The baseline AB of a triangulation system is equal to 400 m long. Stations Cand D are other points of the triangulation system. The angles observed from A and B are as follows: Angle DAB - 27*30, Angle CAB - 78*30, CBA - 52, and Angle DBC - 30'30. 49 30 70 51 30°30' 27 30' 527 B 400m 78°30' 82 30' Compute the distance DB O 194.55 m • 196.55 m O 195.55 m O 193.55 m
Q3): The following data were collected while running a closed traverse ABCDA. Calculate: Line AB BC CD DA 2- Linear misclosure 3- Traverse precision Length(m) 330 866.8846 411.0045 827 Sum=2435.15 Azimuth 181°25' 89°50' 355°00' 264°18'20" Point A B C 1358.7 D 1323.167 A (calculated) 500 Easting 500 491.84 = = Northing 500 170.1 172.62 582.059 500
Given in the accompanying tabulation are the observed data for an open traverse which was made between stations A and E. Line Length Azimuth from North Latitude Departure AB 518.32 BC 594.08 54°50' 79°18' CD 936.76 130°05' DE 425.89 22°35' Determine the following: 1. Shortest distance between the stations A and E 2,, Direction of line AE. (Bearing] Assume that the observed data are correct and without error.
Using the previous exomple, bolance the departures and latitudes using the transit rule. Correer DEP (DEP of course) Corrur"ELAT (LAT of course) OEVALUATE Compute the area of the given traverse using DPD and DMD method. COURSE LENGTH (m) BEARING AB 495.85 NOS" 30' E BC 850.62 N 46° 02' E CD 855.45 S 67* 38 E DE 1020.87 S 12* 25 E EF 1117.26 S 83* 44' W FA 660.08 N 55" 09' W ERSITY
LATITUDES AND DEPARTURES. Given in the accompanying tabulations are the observed data pertaining to four diffe rent traverses: Compute and tabulate the latitudes and departures of each course. LINE LENGTH BEARING LINE AB BC CD DA 732.72m Noo42'E 324.78 S85'57'E 477.24 S03°04'w 388.08 S52'51'w JK KL LM MJ AZIMUTH DISTANCE FROM SOUTH 430.05 m 242°30' 425.18 353°15' 357.20 99°45 183.18 154.00! COURSE LENGTH COURSE LENGTH BEARING 1-2 2-3 3-4 4-5 161.46 m 180.49 171.83 229.70 130.55 AZIMUTH FROM NORTH 228°20' 267°43' 352'oi' 8212 13148 1-2 2-3 3-4 4-5 5-1 427.00 m 301.95 445.66 326.73 434.50 N59°33'E S3913'E S06°35'w NI 7°48'w N70*59'w 5-1
Q3): The following data were collected while running a closed traverse ABCDA. Calculate: 1- Coordinates of B (Easting and Northing). N Line AB BC CD DA 4- Interior angles A and B 5- Distance BC and CD. Length (m) 330 827 Sum= 2435.15 Azimuth 181°25' 89°50' 355°00' 264°18'20" Point A B C D A (calculated) = Easting 500 B 1323.167 Northing 500 582.059 A= B= Angles