1. Methane can be chlorinated by free radical substitution. A very large excess of methane (CH4) is required for the formation of chloromethane. A mixture of methane and chlorine is stable at room temperature. However, the component of mixture reacted rapidly upon exposure to visible light. The reaction begins with the photochemically induced homolytic cleavage the CL-Cl bond to produce two chlorine atoms (Cl). One of the chlorine atoms collides with methane to form HCl and creates a new methyl radical (CH3) in the first propagation reaction. The methyl radical is then reacted with Cl₂ molecules to form chloromethane (CH3CI) and chlorine atom (Cl) in the second propagation step. The two propagation steps continue until the concentrations of Cl₂ and CH4 were reduced. Hence, the reaction between two radicals of Cl and CH3 become significant in termination step and form another chloromethane molecules (CH3CI). A. Based on the sequence of chain reaction stated above, propose the overall mechanism of reaction. B. By considering the pseudo-steady state (PSS) approximation for radical/intermediate species, develop a rate law equation for the formation of chloromethane (CH3Cl) based on the proposed mechanism in (a) if the reaction was conducted in plug flow reactor (PFR)

Chemistry: An Atoms First Approach
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Chapter3: Bonding: General Concepts
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1. Methane can be chlorinated by free radical substitution. A very large excess of methane (CH4) is required for the formation of chloromethane. A mixture of methane and chlorine is stable at room temperature. However, the component of mixture reacted rapidly upon exposure to visible light. The reaction begins with the photochemically induced homolytic cleavage the CL-Cl bond to produce two chlorine atoms (Cl). One of the chlorine atoms collides with methane to form HCl and creates a new methyl radical (CH3) in the first propagation reaction. The methyl radical is then reacted with Cl₂ molecules to form chloromethane (CH3CI) and chlorine atom (Cl) in the second propagation step. The two propagation steps continue until the concentrations of Cl₂ and CH4 were reduced. Hence, the reaction between two radicals of Cl and CH3 become significant in termination step and form another chloromethane molecules (CH3CI).

A. Based on the sequence of chain reaction stated above, propose the overall mechanism of reaction.

B. By considering the pseudo-steady state (PSS) approximation for radical/intermediate species, develop a rate law equation for the formation of chloromethane (CH3Cl) based on the proposed mechanism in (a) if the reaction was conducted in plug flow reactor (PFR).

*Homolytic cleavage is a breaking of covalent bond in which the bonding electron pair is
split evenly between the products and forms radicals.
Useful formula:
-b±Vb²-4ac
For the general quadratic equation ax² + bx + c = 0, x =
2a
Transcribed Image Text:*Homolytic cleavage is a breaking of covalent bond in which the bonding electron pair is split evenly between the products and forms radicals. Useful formula: -b±Vb²-4ac For the general quadratic equation ax² + bx + c = 0, x = 2a
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