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- Respiratory Rate Researchers have found that the 95 th percentile the value at which 95% of the data are at or below for respiratory rates in breath per minute during the first 3 years of infancy are given by y=101.82411-0.0125995x+0.00013401x2 for awake infants and y=101.72858-0.0139928x+0.00017646x2 for sleeping infants, where x is the age in months. Source: Pediatrics. a. What is the domain for each function? b. For each respiratory rate, is the rate decreasing or increasing over the first 3 years of life? Hint: Is the graph of the quadratic in the exponent opening upward or downward? Where is the vertex? c. Verify your answer to part b using a graphing calculator. d. For a 1- year-old infant in the 95 th percentile, how much higher is the walking respiratory rate then the sleeping respiratory rate? e. f.If your graphing calculator is capable of computing a least-squares sinusoidal regression model, use it to find a second model for the data. Graph this new equation along with your first model. How do they compare?Finally, the researcher considers using regression analysis to establish a linear relationship between the two variables – hours worked per week and yearly income. Hours per week Yearly Income ('000's) 18 43.8p 13 44.5 18 44.8 25.5 46.0 11.5 41.2 18 43.3 16 43.6 27 46.2 27.5 46.8 30.5 48.2 24.5 49.3 32.5 53.8 25 53.9 23.5 54.2 30.5 50.5 27.5 51.2 28 51.5 26 52.6 25.5 52.8 26.5 52.9 33 49.5 15 49.8 27.5 50.3 36 54.3 27 55.1 34.5 55.3 39 61.7 37 62.3 31.5 63.4 37 63.7 24.5 55.5 28 55.6 19 55.7 38.5 58.2 37.5 58.3 18.5 58.4 32 59.2 35 59.3 36 59.4 39 60.5 24.5 56.7 26 57.8 38 63.8 44.5 64.2 34.5 55.8 34.5 56.2 40 64.3 41.5 64.5 34.5 64.7 42.3 66.1 34.5 72.3 28 73.2 38…
- Finally, the researcher considers using regression analysis to establish a linear relationship between the two variables – hours worked per week and yearly income. Hours per week Yearly Income ('000's) 18 43.8p 13 44.5 18 44.8 25.5 46.0 11.5 41.2 18 43.3 16 43.6 27 46.2 27.5 46.8 30.5 48.2 24.5 49.3 32.5 53.8 25 53.9 23.5 54.2 30.5 50.5 27.5 51.2 28 51.5 26 52.6 25.5 52.8 26.5 52.9 33 49.5 15 49.8 27.5 50.3 36 54.3 27 55.1 34.5 55.3 39 61.7 37 62.3 31.5 63.4 37 63.7 24.5 55.5 28 55.6 19 55.7 38.5 58.2 37.5 58.3 18.5 58.4 32 59.2 35 59.3 36 59.4 39 60.5 24.5 56.7 26 57.8 38 63.8 44.5 64.2 34.5 55.8 34.5 56.2 40 64.3 41.5 64.5 34.5 64.7 42.3 66.1 34.5 72.3 28 73.2 38…Here, mean of X is 3 and the mean of Y is 7. The regression line that predicts Y from X necessarily goes through the point (3,7). True FalseIf I add the additional condition which is the labor is female using the following: #People who is femalefemale = x*0.46 Will it become dependent variable and how will I do linear regression model by adding this condition?
- Select all the charts that violate the conditions for linear regression. These are residual plots so the red line represents the average residual, zero. 미 Od (a) (d) 매 Get help: Video (b) (e) (c) (1)Step 9 (d) What proportion of the observed variation in efficiency ratio can be attributed to the simple linear regression relationship between the two variables? The proportion of the observed variation in efficiency ratio which can be attributed to the simple linear regression relationship is equal to the coefficient of determination, r². r² = 1- SSE SST' where SSE = Syy - B₁Sxy, and SST = Syy. First, use v² = 77.1001, (v₁)² = (40.17)² = 1,613.6289, and n = 24 to calculate Sy yy' Swy = y? - = 77.1001 n Since SST = S, 1,613.6289 24 Syy, it follows that SST = Submit Skip (you cannot come back) rounded to six decimal places.A sales manager wants to examine the relationship between the number of daily customers (x) and the revenue generated (y). For this purpose, he made observations in a randomly chosen 6 days for a store and observed the number of daily customers and the revenue (1000 TL). The personally created data set for the x and y variables is included in the attached “Homework data” file. Using the data set defined on your behalf; x1 x2 x3 x4 x5 x6 y1 y2 y3 y4 y5 y6 sb1 Burak data 74 86 96 105 110 124 290 307 331 406 421 481 0.491 a) Create the regression equation b) Interpret b0 and b1 values c) Test and interpret whether there is a linear relationship between the number of daily customers and the income obtained at the level of α = 0.05 significance. Could you explain this question again and in more detail especially not in excel image
- A sales manager wants to examine the relationship between the number of daily customers (x) and the revenue generated (y). For this purpose, he made observations in a randomly chosen 6 days for a store and observed the number of daily customers and the revenue (1000 TL). The personally created data set for the x and y variables is included in the attached “Homework data” file. Using the data set defined on your behalf; x1 x2 x3 x4 x5 x6 y1 y2 y3 y4 y5 y6 sb1 Burak data 74 86 96 105 110 124 290 307 331 406 421 481 0.491 a) Create the regression equation b) Interpret b0 and b1 values c) Test and interpret whether there is a linear relationship between the number of daily customers and the income obtained at the level of α = 0.05 significance. d) Establish and interpret the 95% confidence interval for β1.A sales manager wants to examine the relationship between the number of daily customers (x) and the revenue generated (y). For this purpose, he made observations in a randomly chosen 6 days for a store and observed the number of daily customers and the revenue (1000 TL). The personally created data set for the x and y variables is included in the attached “Homework data” file. Using the data set defined on your behalf; x1 x2 x3 x4 x5 x6 y1 y2 y3 y4 y5 y6 sb1 Burak data 74 86 96 105 110 124 290 307 331 406 421 481 0.491 d) Establish and interpret the 95% confidence interval for β1.For the linear regression model Y = bo + b1(X): The p-value for the intercept is large: about 0.98 The p-value for the slope is very small: less than 2 times 10^(-16) What can we conclude? Since the p-value for the intercept is large, we can conclude that there is not a strong correlation between X and Y. Since the p-value for the intercept is large, we can conclude that there is a very strong correlation between X and Y. Since the p-value for the slope is very small, we can conclude that there is a very weak correlation between X and Y. Since the p-value for the slope is very small, we can conclude that there is a very strong correlation between X and Y. We are not able to assess the strength of the correlation between X and Y with the output provided.