1. An AISI 1018 steel has a yield strength, Sy= 295 MPa. Using the distortion-energy theory for the given state of plane stress, (a) determine the factor of safety, (b) plot the failure locus, the load line, and estimate the factor of safety by graphical measurement. Tx (MPa) 75 -100 100 -30 -80 Ty (MPa) 3.5 30 0 -65 30 Txy (MPa) 0 0 25 40 -10

Elements Of Electromagnetics
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Author:Sadiku, Matthew N. O.
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1. An AISI 1018 steel has a yield strength, Sy = 295 MPa. Using the distortion-energy theory for the given
state of plane stress, (a) determine the factor of safety, (b) plot the failure locus, the load line, and estimate
the factor of safety by graphical measurement.
(Tx (MPa)
75
-100
100
-30
-80
Ty (MPa)
3.5
30
0
x (kpsi)
150
150
125
80
125
-65
30
2. An AISI 4142 steel Q&T at 800°F exhibits Syt = 235 kpsi, Syc = 285 kpsi, and & = 0.07. For the
given state of plane stress, (a) determine the factor of safety, (b) plot the failure locus and the load line and
estimate the factor of safety by graphical measurement.
y (kpsi)
-50
50
Txy (MPa)
0
0
()
125
80
25
40
-10
Txy (kpsi)
0
0
-75
50
75
Transcribed Image Text:1. An AISI 1018 steel has a yield strength, Sy = 295 MPa. Using the distortion-energy theory for the given state of plane stress, (a) determine the factor of safety, (b) plot the failure locus, the load line, and estimate the factor of safety by graphical measurement. (Tx (MPa) 75 -100 100 -30 -80 Ty (MPa) 3.5 30 0 x (kpsi) 150 150 125 80 125 -65 30 2. An AISI 4142 steel Q&T at 800°F exhibits Syt = 235 kpsi, Syc = 285 kpsi, and & = 0.07. For the given state of plane stress, (a) determine the factor of safety, (b) plot the failure locus and the load line and estimate the factor of safety by graphical measurement. y (kpsi) -50 50 Txy (MPa) 0 0 () 125 80 25 40 -10 Txy (kpsi) 0 0 -75 50 75
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