デジタル形式で段階的に解決SOLVE STEP BY STEP IN DIGITAL FORMAT1. A particle travels in space according to the function:* = 2tî + (5t²-t)j + 3t² kand its velocity is:= 21+ (10t - 1)ĵ + 6tka. At t = 2, what is the position of the particle?ありがとう!!b. At t = 2, what is the velocity of the particle?c. At t = 2, what is the cross product between the velocity and the position?d. At t = 2, what is the dot product between the velocity and the position?-

The given position of a particle and its velocity .The objective is to find the position vector and…

1. A particle travels in space according to the function: 7 = 2tî + (5t² - t)ĵ + 3t²k and its velocity is: = 2 + (10t - 1)j + 6tk a. At t = 2, what is the position of the particle? b. At t = 2, what is the velocity of the particle? c. At t = 2, what is the cross product between the velocity and the position? d. At t = 2, what is the dot product between the velocity and the position?