1. A configuration of charges is shown below. q = 5 nC0Enet-2q=5+q+3q10The electric fields due to the charges -2q, +q, +3q, and -q at x = 11 cm are shown below.The direction of the electric field due to a point charge at any point is along the line joining the chargeand the point and away from the charge for a positive charge and towards the charge for a negativecharge.Ex (cm)-E-9E 20x= 11 cmThe electric fields due to -2q at x = 11 cm is in the negative x-direction, and due to -q, +q and +3q is inthe positive x-direction. The strength of the field is determined by the charge and the distancebetween the charge and the point.The net electric field in Part 1 will point in the positive x-direction.(a) Find the total electric field at x = 11 cm.NCta EE +34

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1. A configuration of charges is shown below. q = 5 nC 0 Enet -2q = 5 +q +3q 10 The electric fields due to the charges -2q, +q, +3q, and -q at x = 11 cm are shown below. The direction of the electric field due to a point charge at any point is along the line joining the charge and the point and away from the charge for a positive charge and towards the charge for a negative charge. E x (cm) 9 Ε -9 E 20 x= 11 cm The electric fields due to -2q at x = 11 cm is in the negative x-direction, and due to -q, +q and +3q is in the positive x-direction. The strength of the field is determined by the charge and the distance between the charge and the point. The net electric field in Part 1 will point in the positive x-direction. (a) Find the total electric field at x = 11 cm. N C + E E +34

1. A configuration of charges is shown below. q = 5 nC 0 Enet -2q = 5 +q +3q 10 The electric fields due to the charges -2q, +q, +3q, and -q at x = 11 cm are shown below. The direction of the electric field due to a point charge at any point is along the line joining the charge and the point and away from the charge for a positive charge and towards the charge for a negative charge. E x (cm) 9 Ε -9 E 20 x= 11 cm The electric fields due to -2q at x = 11 cm is in the negative x-direction, and due to -q, +q and +3q is in the positive x-direction. The strength of the field is determined by the charge and the distance between the charge and the point. The net electric field in Part 1 will point in the positive x-direction. (a) Find the total electric field at x = 11 cm. N C + E E +34

Principles of Physics: A Calculus-Based Text

5th Edition

ISBN:9781133104261

Author:Raymond A. Serway, John W. Jewett

Publisher:Raymond A. Serway, John W. Jewett

Chapter19: Electric Forces And Electric Fields

Section: Chapter Questions

Problem 28P: Three equal positive charges q are at the comers of an equilateral triangle of side a as shown in...

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