1. A circular curve of radius 500 metres is to be constructed between two straights of a proposed highway. The deflection angle between the straight is 22° 30' 00" and the curve is to be set out by the tangential angles method using a theodolite and a tape. The through chainage of the intersection point is 3345.00. Calculate the tangent lengths Calculate the length of the circular curve Calculate the through chainages of the two tangent points i)

1. A circular curve of radius 500 metres is to be constructed between two straights of a proposed highway. The deflection angle between the straight is 22° 30' 00" and the curve is to be set out by the tangential angles method using a theodolite and a tape. The through chainage of the intersection point is 3345.00. Calculate the tangent lengths Calculate the length of the circular curve Calculate the through chainages of the two tangent points i)

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

See similar textbooks

Similar questions

1. A circular curve of radius 500 metres is to be constructed between two straights of a proposed highway. The deflection angle between the straight is 22° 30' 00" and the curve is to be set out by the tangential angles method using a theodolite and a tape. The through chainage of the intersection point is 3345.00. iv) v) vi) vii) Calculate the long chord Calculate the mid-ordinate ((PS) of the circular curve Calculate the external distance (PI) The pegs are required on the centre line at exact 20 metre multiples of through chainage. Tabulate the data required to set out the curve from entry tangent point (T).
1. A circular curve of radius 500 metres is to be constructed between two straights of a proposed highway. The deflection angle between the straight is 22° 30' 00" and the curve is to be set out by the tangential angles method using a theodolite and a tape. The through chainage of the intersection point is 3345.00. i) The pegs are required on the centre line at exact 20 metre multiples of through chainage. Tabulate the data required to set out the curve from entry tangent point (T).
QUESTION 3 The length of the common tangent of a compound curve is equal to 68.62 m. The common tangent makes an angle of 12° and 18°, respectively to the tangents of the compound curve. If the length of the tangent of the first curve is equal to 41.02 m, determine: a. radius of the second curve Answer: R₂= b. radius of the first curve Answer: R₁= c. the stationing of PT if PC is at 20+042.20 Answer: Sta PT= m m Note: Unit has been provided after the blank space. No need to indicate units on your answer.
1. A circular curve of radius 500 metres is to be constructed between two straights of a proposed highway. The deflection angle between the straight is 22° 30' 00" and the curve is to be set out by the tangential angles method using a theodolite and a tape. The through chainage of the intersection point is 3345.00. vii) The pegs are required on the centre line at exact 20 metre multiples of through chainage. Tabulate the data required to set out the curve from entry tangent point (T).
Show your COMPLETE solution in 3 decimal places. Provide illustration and label accordingly. 4.A simple curve having a radius of 229.18m has a back tangent of N28 ̊E and a forward tangent of N66 ̊E. A property line runningparallel to the back tangent crosses the curve at a distance of 10m from it. If the PC of thecurve is at 10+120.6. (a) What is the deflection angle at the point of intersection of the property line and the curve measured from the tangent at station 10+120.6, (b) What is the stationing at the point of intersection of the property line and the curve, and (c) Compute the chord distance from the PC to the point of intersection of the property line and the curve?
Pls. Write your own solution. A reverse curve connects two converging tangents intersecting at an angle of 30 degrees. The distance of this intersection from the PI of the curve is 150 meters. The deflection angle of the common tangent from the back tangent is 20 degrees (first curve) and the azimuth of the common tangent is 320 degrees. The degree of curve of the second simple curve is 6 degrees and the stationing of the point of intersection of the first curve is 4+450. Determine the stationing of the PC, PRC, and PT. Use the formula R=1145.916/D
The railroad track is laid out parallel to the forward tangent of the simple curve at a perpendicular distance of 10 m. the point of intersection between the curve and the railroad has a deflection angle of 4 degrees from the forward tangent. Determine the radius of the curve.a.2755.10 m b. 1027.55 m c.289.65 m d. 644.53 m
QUESTION 2 Two tangents AB and BC intersect at an angle of 24°0'0". A curve is formed from point A to C. A point on the curve, D, is found along the curve near A. Point D is located 21.03 m from point B, and has a perpendicular distance of 2.79 m from line AB. a. Calculate the radius of the simple curve connecting the two tangents and passing point D Answer: R= m b. Calculate the length of the chord connecting PC and point D Answer: C = m Note: Unit has been provided after the blank space. No need to indicate units on your answer. Use sexagesimal units for angle measurements.
SET A 3. A highway intersection 40° is to be constructed by a 6 simple curve and a spiral curve on each end of the simple curve. The design speed of the spiral curve is 0.93miles per minute. Use arc basis. a. Compute the length of throw in meters. b. Compute the length of the tangent of a spiral easement curve, C. What is the total length of curve in meters?
a) A horizontal curve with a deflection angle of 60°30' and degree of curvature of 5° as shown in Figure 5 is to be set out at whole station intervals of 10ft. If the point cof curvature (PC) is located at a station 121+25.66, determine. i, the length of the curve and the station of PT ii. the deflection angles VAp, VAq, VAv and Vas (AN,10) PI V. 100ft 100ft PC 1, 200ft PT A, D /6. Figure 5: A horizontal curve
A simple curve has a central angle of 35 degrees and a degree of curve of 6 degree. P.I. is at STA 0+071.54. The bearing of back tangent is N 45° E. Draw the figure. (a.) Compute all elements of the curve. (b.) Determine the Stationing of P.C. and P.T. (c.) Prepare a field note using deflection method.
Q2/ setting out of curve by perpendicular offsets from tangent lines when deflection angle of interval = 10 22°48'; R=127.30assume