PYTHON CS1 PROBLEM Define a function that takes a dictionary gdict as a parameter and returns a list of values that are associated with only a single key in the dictionary. For example: 1. If gdict = {"a":3, "b": 4, "x": 3, "z": 5, "k": 4, "c": 1) then your function should return the list [1, 5]. 3 and 4 are not in the returned list because they are associated with more than one key. 2. If gdict = {"a":3, "b": 4, "x": 3, "k": 4) then your function should return the list []. 3. If gdict = {} then your function should return the list [].

PYTHON CS1 PROBLEM Define a function that takes a dictionary gdict as a parameter and returns a list of values that are associated with only a single key in the dictionary. For example: 1. If gdict = {"a":3, "b": 4, "x": 3, "z": 5, "k": 4, "c": 1) then your function should return the list [1, 5]. 3 and 4 are not in the returned list because they are associated with more than one key. 2. If gdict = {"a":3, "b": 4, "x": 3, "k": 4) then your function should return the list []. 3. If gdict = {} then your function should return the list [].

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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struct insert_at_back_of_dll { // Function takes a constant Book as a parameter, inserts that book at the // back of a doubly linked list, and returns nothing. void operator()(const Book& book) { / // TO-DO (2) |||| // Write the lines of code to insert "book" at the back of "my_dll". // // // END-TO-DO (2) ||| } std::list& my_dll; };
PYTHON CS1 PROBLEM Define a function that takes a dictionary gdict as a parameter and returns a list of values that are associated with only a single key in the dictionary. For example: 1. If gdict = {"a":3, "b": 4, "x": 3, "z": 5, "k": 4, "c": 1} then your function should return the list [1, 5]. 3 and 4 are not in the returned list because they are associated with more than one key. 2. If gdict = {"a":3, "b": 4, "x": 3, "k": 4) then your function should return the list []. 3. If gdict = {} then your function should return the list [].
Concatenate Map This function will be given a single parameter known as the Map List. The Map List is a list of maps. Your job is to combine all the maps found in the map list into a single map and return it. There are two rules for addingvalues to the map. You must add key-value pairs to the map in the same order they are found in the Map List. If the key already exists, it cannot be overwritten. In other words, if two or more maps have the same key, the key to be added cannot be overwritten by the subsequent maps. Signature: public static HashMap<String, Integer> concatenateMap(ArrayList<HashMap<String, Integer>> mapList) Example: INPUT: [{b=55, t=20, f=26, n=87, o=93}, {s=95, f=9, n=11, o=71}, {f=89, n=82, o=29}]OUTPUT: {b=55, s=95, t=20, f=26, n=87, o=93} INPUT: [{v=2, f=80, z=43, k=90, n=43}, {d=41, f=98, y=39, n=83}, {d=12, v=61, y=44, n=30}]OUTPUT: {d=41, v=2, f=80, y=39, z=43, k=90, n=43} INPUT: [{p=79, b=10, g=28, h=21, z=62}, {p=5, g=87, h=38}, {p=29,…
PYTHON CS1 PROBLEM Define a function that takes a list of lists, glol, as a parameter. You may assume that the inner lists in glol are lists of positive integers. Your function should return True if at least one of the inner lists in glol contains two or more multiples of 10. Otherwise it should return False. For example: If glol = [ ] then your function returns False. If glol = [[ ], [4, 2]] then your function returns False. If glol = [[10, 2, 6, 8], [12, 6], [15, 20, 5]] then your function returns False. If glol = [[10, 2, 6], [12, 6], [10, 2, 70, 15], [15, 10, 5]] then your function returns True as the inner list [10, 2, 70, 15] contains 10 and 70. If glol = [[10, 2, 6], [12, 6], [10, 7, 15], [50, 10, 50, 4, 6]] then your function returns True as the inner list [50, 10, 50, 4, 6] contains 50 twice. 6. If glol = [[10, 20, 6, 90], [12, 6], [ 7, 3, 15], [50, 10, 50, 4, 7]] then your function returns True as the inner lists [50, 10, 50, 4, 7] and [10, 20, 6, 90] contain more…
struct insert_at_back_of_sll { // Function takes a constant Book as a parameter, inserts that book at the // back of a singly linked list, and returns nothing. void operator()(const Book& book) { /// TO-DO (3) /// // Write the lines of code to insert "book" at the back of "my_sll". Since // the SLL has no size() function and no tail pointer, you must walk the // list looking for the last node. // // HINT: Do not attempt to insert after "my_sll.end()". // ///// END-T0-DO (3) ||||// } std::forward_list& my_sll; };
struct remove_from_front_of_dll { // Function takes no parameters, removes the book at the front of a doubly // linked list, and returns nothing. void operator()(const Book& unused) { //// TO-DO (13) |||| // Write the lines of code to remove the book at the front of "my_dll", // // Remember, attempting to remove an element from an empty data structure is // a logic error. Include code to avoid that. ///// END-TO-DO (13) //// } std::list& my_dll; };
python: def traditions_dict(adict): """ Question 6 Given a dictionary that maps a person to a list of their favorite traditions, return a dictionary with the value being the list sorted by the last letter of each tradition. If two traditions have the same last letter, sort by the first letter. HINT: This will require the use of lambda functions Args: adict (dict) Returns: dict >>> traditions_dict({"Jacob": ["The Horse", "Stealing the t", "Midnight Bud"], "Athena": ["Mini Five-Hundred", "Freshman Cake Race", "Buzzweiser Song"], "Liv": ["Freshman Cake Race", "George P. Burdell", "Buzzweiser Song"]}) {'Jacob': ['Midnight Bud', 'The Horse', 'Stealing the t'], 'Athena': ['Mini Five-Hundred', 'Freshman Cake Race', 'Buzzweiser Song'], 'Liv': ['Freshman Cake Race', 'Buzzweiser Song', 'George P. Burdell']} >>> traditions_dict({"Madison": ["The Horse", "Midnight Bud", "Buzzweiser…
get_movie_dict() takes a 2-D list similar to movie_db and a dictionary similar to ratings as the parameters and returns a dictionary, where each {key: value} of this dictionary is {a valid movie id: a list containing the name of the movie, the year it got released, and the average rating of this movie}. I will refer to this dictionary as movies.>>> movies = get_movie_dict(movies_db, ratings)>>> display_dict(movies)1: ['Toy Story', 1995, 3.92]2: ['Jumanji', 1995, 3.43]3: ['Grumpier Old Men', 1995, 3.26]4: ['Waiting to Exhale', 1995, 2.36]5: ['Father of the Bride Part II', 1995, 3.07]6: ['Heat', 1995, 3.95]7: ['Sabrina', 1995, 3.19]8: ['Tom and Huck', 1995, 2.88]9: ['Sudden Death', 1995, 3.12]10: ['GoldenEye', 1995, 3.5]11: ['American President The', 1995, 3.67]12: ['Dracula: Dead and Loving It', 1995, 2.42]13: ['Balto', 1995, 3.12]14: ['Nixon', 1995, 3.83]15: ['Cutthroat Island', 1995, 3.0]16: ['Casino', 1995, 3.93]17: ['Sense and Sensibility', 1995, 3.78]18: ['Four…
Make List Items Uppercase 2 in python Define the function make_uppercase(mylist), which takes a list parameter mylist (a list of strings), mutates the list by uppercasing each string in mylist. The function returns None. For example, if mylist is ['cat', 'Dog', 'frOG'], then the mutated list should be ['CAT', 'DOG', 'FROG']. For example: Test Result mylist = ['cat', 'Dog', 'frOG'] result = make_uppercase(mylist) print(mylist) if result != None: print("Error, return value should be None") ['CAT', 'DOG', 'FROG'] mylist = ['baNanas', 'appLes', 'pEAches', 'PEArs'] result = make_uppercase(mylist) print(mylist) if result != None: print("Error, return value should be None") ['BANANAS', 'APPLES', 'PEACHES', 'PEARS']
C++ Programming Language ::::::: Redo the same functions this time as nonmember functions please : NOTE: You can add only one function into the linked list class get_at_position which will return value of element at given position. 1) Insert before tail : Insert a value into a simply linked list, such that it's location will be before tail. So if a list contains {1, 2, 3}, insert before tail value 9 is called, the list will become {1, 2, 9, 3}. 2) Insert before value : Insert a value into a simply linked list, such that it's location will be before a particular value. So if a list contains {1, 2, 3}, insert before 2 value 9 is called, the list will become {1, 9, 2, 3}. 3)Count common elements : Count common values between two simply linked lists.So if a list1 contains {1, 2, 3, 4, 5}, and list2 contains {1, 3, 4, 6}, number of common elements is 3. 4) Check if sorted : Check if elements of simply linked lists are sorted in ascending order or not.So if a list contains {1, 3, 7, 8, 9}…
Write a function named dictMax which takes two arguments: a dictionary and a list. Your function must look for the keys provided in the list argument, within the dictionary argument and return the maximum of the corresponding values. For example: dictMax({1:3, 3:2, 4:5, 2:6, 7:-1, 6:-3}, [3,2,6]) will return 6, because key 3 in the dictionary corresponds to value 2, key 2 to value 6 and key 6 to value -3, and among 2, 6 and -3, the maximum is 6. If a key does not exist in the dictionary, you should omit it. If none of the keys exist in the dictionary, you should return None.
in c++ In a linked list made of integer data type, write only an application file that prints thoseintegers that are divisible by 5. Note that you assume that linked list exists, you onlyprints the value of data items that meet the condition (divisible by 5)