1 atm, how much energy is required to heat 61.0 g H,O(s) at -10.0 °C to H,O(g) at 119.0 °C? Use the heat transfer nstants found in this table.
1 atm, how much energy is required to heat 61.0 g H,O(s) at -10.0 °C to H,O(g) at 119.0 °C? Use the heat transfer nstants found in this table.
Chemistry by OpenStax (2015-05-04)
1st Edition
ISBN:9781938168390
Author:Klaus Theopold, Richard H Langley, Paul Flowers, William R. Robinson, Mark Blaser
Publisher:Klaus Theopold, Richard H Langley, Paul Flowers, William R. Robinson, Mark Blaser
Chapter5: Thermochemistry
Section: Chapter Questions
Problem 3E: Explain the difference between heat capacity and specific heat of a substance.
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Transcribed Image Text:At 1 atm, how much energy is required to heat 61.0 g H,O(s) at – 10.0 °C to H,O(g) at 119.0 °C? Use the heat transfer
constants found in this table.
kJ
Expert Solution
Step 1
The process is carried in 5 stages
To heat ice from -10° to 0° C
Q = mc∆T
= 61×2.087× 10
= 1273.07 J
2) To melt the ice at 0°C to water at 0°C.
Q = m x Enthalpy of fusion
= 61 g x 333.6 J/g
= 20349.6 J
Q = 20349.6 J
3) To heat the water from 0°C to boiling at 100°C
Q = mcdT where c = specific heat of water , dT = 100°C
= 61 g x 4.184 J/g/°C x 100°C
= 25522.4 J
Q = 25522.4 J
4) To vaporize the water to steam at 100°C
Q = m x Enthalpy of vaporization
= 61 g x 2257 J/g
= 137677 J
Q = 137677 J.
5)
) To heat the steam from 100°C to 119°C
Q = mcdT where c = specific heat of gaseous H2O (steam) , dT = 19°C
= 61 g x 2.000 J/g/°C x 100°C
= 2318 J
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