You eventually determine that ATP has a negative AG value. In a cell, the AG of ATP hydrolysis is -7.3 kcal/mol. Refer to the diagram of glycolysis below. Given what you know about ATP, what could be the AG of converting Intermediate 9 to intermediate 10 during glycolysis?ENERGY-INVESTINGENERGY-HARVESTINGChange in standard free energy (kcal/mol)-50-100REACTIONS+16.0 kcal/mol+14.0 kcal/mol-14 kcal/mol-16 kcal/molQuestion 42TrueATPQuestion 432 3GlucoseREACTIONSGlyceraldehyde-3-phosphate[6]2 NAD+-150Each glucose yields: 2 Pyruvate, 2 ATP, 2 NADH + 2 H+7In a cell, the AG of ATP hydrolysis is -7.3 kcal/mol. This indicates that:NADH+H2ATP10PyruvateThe products of ATP hydrolysis are more stable than the reactants.The products of ATP hydrolysis are less stable than the reactants.The products of ATP hydrolysis and the reactants have approximately equal stability.T/F: Glycolysis is an example of a catabolic pathway. Therefore, over the course of glycolysis, entropy decreases.

Glycolysis is the first step of aerobic or anaerobic respiration. It is a 10 step reaction and each…

0 0 3 pl ol Glucose 3-phosphate -2 NAD+ 2 (NADH + H ATP Pyruvate 0 ch glucose yields: 2 Pyruvate, 2 ATP, 2 NADH + 2 H+ of ATP hydrolysis is -7.3 kcal/mol. This indicates that: of ATP hydrolysis are more stable than the reactants. of ATP hydrolysis are less stable than the reactants. of ATP hydrolysis and the reactants have approximately equal stability. an example of a catabolic pathway. Therefore, over the course of glycolysis, entropy decreases.

0 0 3 pl ol Glucose 3-phosphate -2 NAD+ 2 (NADH + H ATP Pyruvate 0 ch glucose yields: 2 Pyruvate, 2 ATP, 2 NADH + 2 H+ of ATP hydrolysis is -7.3 kcal/mol. This indicates that: of ATP hydrolysis are more stable than the reactants. of ATP hydrolysis are less stable than the reactants. of ATP hydrolysis and the reactants have approximately equal stability. an example of a catabolic pathway. Therefore, over the course of glycolysis, entropy decreases.

Human Physiology: From Cells to Systems (MindTap Course List)

9th Edition

ISBN:9781285866932

Author:Lauralee Sherwood

Publisher:Lauralee Sherwood

Chapter2: Cell Physiology

Section: Chapter Questions

Problem 2SQE

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Similar questions

You know that the free energy of ATP hydrolysis depends on the ATP/ADP ratio. Given that under standard conditions DGo = -30.5 kJ/mol, what should be DG of ATP hydrolysis under normal intracellular concentrations? [ATP] = 2.3 mM, [ADP] = 0.25 mM, [Pi] = 1.65 mM What is the energy of ATP hydrolysis in a cell that is ATP-depleted? [ATP] = 0.1 mM, [ADP] = 2.8 mM, [Pi] = 1.65 mM
As a result of an experiment following measurements were obtained from a cell: ATP concentration of 0.5 mM, ADP concentration of 0.1 mM, inorganic phosphate (Pi) concentration of 2 mM. Under these conditions calculate the actual free energy (AG) of the reaction of hydrolysis of ATP to ADP and Pi. (The standard energy (AG°) of ATP = -31 kJ/mol; RT = 2,58 kJ/mol) Select one: O a. -28 kJ/mol O b. -33 kJ/mol OC. -19 kJ/mol O d. -42 kJ/mol
In the third step of glycolysis, the given reactions are coupled. reaction 1: fructose-6-phosphate + Pi ⟶ fructose-1,6-bisphosphate + H2O (Δ? = −28 kJ/mol) reaction 2: ATP + H2O ⟶ ADP + Pi (Δ? = +13.8 kJ/mol) Calculate the overall ΔG (kJ/mol) for the coupled reaction.
If the DGo for ATP hydrolysis into ADP + inorganic phosphate is -7.3 kcal/mole, and the DGo for sucrose synthesis from glucose + fructose is +5.5 kcal/mole, calculate standard free energy change for the combined reaction of ATP + glucose + fructose g ADP + sucrose + inorganic phosphate. DGo = -12.8 kcal/mole DGo = -1.8 kcal/mole DGo = 0 kcal/mole DGo = +1.8 kcal/mole DGo = +12.8 kcal/mole
The first reaction in Glycolysis is the phosphorylation of Glucose:Pi + Glucose → Glucose 6-Phosphate + waterThis is a thermodynamically unfavorable process with a ∆G0’ = +13.8 kJ/mol. In a liver cell at370C the concentrations of both phosphate and glucose are normally maintained at about 0.005 M each. What would be the equilibrium concentration of Glucose 6-Phosphate according to the above data? Note: In the biochemical standard state [H2O] = 1.0 a. 0.00000012 b. 0.0000025 c. 0.00000025 d. 0.00474 e. 0.005 f. 1.0 g. 0.1 h. 0.25 i. 2.4
Coupled reactions occur where a nonspontaneous reaction is enabled by coupling it to a spontaneous reaction. This approach is common in biological settings. Determine if ATP could be generated by this biochemical reaction. You have calculated that cell potential is +0.637V. An example of a coupled reaction is the first step of glycolysis, the phosphorylation of glucose to form glucose-6-phosphate shown below. kJ/mol The net AG° for this reaction is 1 2 3 н он H. H- H- H H H H 4 6. H. glucose phosphate anion glucose-6-phosphate AG = +14.0 kJ/mol 7 8 9. АТР ADP phosphate anion AG = -30.5 kJ/mol +/- LO
The formation of ATP by ATP Synthase is part of a coupled reaction, as discussed in class. Given the information below and using what you know about ATP Synthase and the proton motive force, calculate the overall AG and determine if the coupled reaction is favorable overall. Note that you do not need to worry about intermediates like we did for the class example. ADP + Pi → ATP has a AG = 7.3 kcal/mol 2 moles of protons traveling back down their gradient across the inner mitochondrial membrane has a AG = -10.28 kcal/mol %3D O a. Overall AG = -17.58 kcal/mol, favorable overall O b. Overall AG = -2.98 kcal/mol, favorable overall %3D O c. Overall AG = 2.98 kcal/mol, unfavorable overall O d. Overall AG = 17.58 kcal/mol, favorable overall
Assume that in a certain cell, the ratio of products/reactants or Keg = 809.5 (Keq is dimensionless) for the reaction Glucose + 2ATP > Glucose-1,6-diP + 2ADP, at a particular instant, the concentrations of each compound were Glucose =2.4M, ATP =11.1M, ADP -12.8M and G-6-P -28.4M. Calculate the difference (dimensionless) between Keq and the ratio of products/ractants at this instance, in this cell, to five decimal places
The AG of the reaction C6H12O6 + 60₂ --> 6CO₂ + 6H₂O is -686 kcal/mol glucose oxidized. The AG of the reaction ADP + P₁ --> ATP + H₂O is + 7.3 kcal/mol ATP synthesized. The oxidation of glucose can be coupled to the synthesis of ATP. If the coupling is 50% efficient, how many molecules of ATP can be synthesized per molecule of glucose oxidized? Round your answer to the nearest whole number.
Free energy changes under intracellular conditions differ markedly from those determined under standard conditions. AG" =-30.5 kJ/mol for ATP hydrolysis to ADP and P,. Calculate AG for ATP hydrolysis in a cell at 37 °C that contains [ATP] =3 mM, [ADP] =1mM, and [P] =1 mM.
The hydrolysis of ATP yields 7.3 kcal/mol of energy. The conversion of phosphoenol pyruvate to pyruvate yields 14.8 kcal/mol of energy. What is AG for the reaction shown below? PEP + ADP→ pyruvate + ATP O -22.1 kcal/mol O 22.1 kcal/mol O -7.5 kcal/mol O 7.5 kcal/mol
The standard free energy of hydrolysis of inorganic polyphosphate (polyP) is about −20 kJ/mol for each Pi released. We calculated in Worked Example 13–2 that, in a cell, it takes about 50 kJ/mol of energy to synthesize ATPfrom ADP and Pi. Is it feasible for a cell to use polyphosphate to synthesize ATP from ADP? Explain your answer.