.4a) What the rate order with respect to the water? Notetreat the volume the water [10mL = 10M] and [20mL = 20N] We can evaluate these assumptions based on the fact we're only attempting ascertan orders that are directly proportion to their respective volumes in case. b.) What is the rate order with respect to the Buffer ? Question-5: Write the correct rate larw expression for the reaction? Question-6: Choose reaction-1 and give the rate law constant k for trial-1.
.4a) What the rate order with respect to the water? Notetreat the volume the water [10mL = 10M] and [20mL = 20N] We can evaluate these assumptions based on the fact we're only attempting ascertan orders that are directly proportion to their respective volumes in case. b.) What is the rate order with respect to the Buffer ? Question-5: Write the correct rate larw expression for the reaction? Question-6: Choose reaction-1 and give the rate law constant k for trial-1.
Chemistry for Engineering Students
4th Edition
ISBN:9781337398909
Author:Lawrence S. Brown, Tom Holme
Publisher:Lawrence S. Brown, Tom Holme
Chapter11: Chemical Kinetics
Section: Chapter Questions
Problem 11.73PAE
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Q.4a) What the rate order with respect to the water? Notetreat the volume the water [10mL = 10M] and [20mL = 20N] We can evaluate these assumptions based on the fact we're only attempting ascertan orders that are directly proportion to their respective volumes in case.
b.) What is the rate order with respect to the Buffer ?
Question-5: Write the correct rate larw expression for the reaction?
Question-6: Choose reaction-1 and give the rate law constant k for trial-1.
Transcribed Image Text:The given data is based on the following chemical reaction:
31 (aq) + H,O,(ag) + 2H;O*(aq) → I, (aq) + 4H,0()
HI
HO
H-O
Buffer
Rate
Trial-1
0.03M
0.0001M
10mL
0.1M
0.2035M/s
Trial-2
0.06M
0.0001M
10mL
0.1M
0.4072M/s
0.03M
0.0002M
10mL
0.1M
0.2041M/3
Trial-3
Trial-4
0.06M
0.0001M
10mL
0.2M
1.6290M/s
Trial-5
0.03M
0.0001M
20mL
10.1M
0.2030M/s
Trial-6
0.015M
0.0001M
10mL
0.1M
0.101SM
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