Miniature Hot Air Balloons and Archimedes's Principle of Buoyancy

1. The volume of the gummy bear increased when we put it in water for twenty four hours. Originally, the volume of the bear was 1.75cm3. After the bear was in the water for twenty four hours, its volume increased to 10.5cm3. So, to find the change in volume, you subtract the new amount from the original. 10.5cm3-1.75cm3= 8.75cm3. The change in volume is 8.75cm3.

Using Archimedes principal I believe the amount of water displaced would have been less due to the buoyancy of the object.

Main Point Two: The measurement of inflated to the uninflated balloon is important throughout the balloon animal process.

Hypothesis: If the egg is placed into water, then it will increase in size since water is a hypotonic liquid because it contains more water than the egg.

Attraction between water molecules which allows insects and other objects to float a top the water

When an object falls onto the surface, it has to push the water molecules apart. If the effect of the weight of the object is insufficient to match the attractive forces between molecules in the surface layer, the object will not enter the surface.

The balloon's meaning is an alarmingly mysterious. The lack of a fixed reason for the balloon creates a lack of trust, frustration, and hostility for the authorities. Experts conduct secret tests to determine ways of removing or destroying the balloon, but because the narrator has hidden the pumps, there was nothing the authorities could do.

The final circumference of the balloon in room temperature water was 37.5. It shrank 4cm less which is a huge surprise since we expected it to stay the same. The final circumference of the balloon in the cold water was 39.5. It shrank 2cm less as it was expected it would shrink. There was no pattern at all.

First we measured two gummy bears and figured out their mass. We put one gummy bear in a ziplock bag and sealed it. Then we measured out 150ml of water and placed it in a cup. We left the gummy bears out for 24 hours. The next day we took the gummy bear in the bag out and measured it to see if it had changed. we then drained all the water out of the plastic cup and attempted to get the measurements. We found the mass for the two gummy bears and then figured out the change in volume. The change in volume for our gummy bear was 121mm for the gummy bear in the plastic bag. Then 4492 mm for the gummy bear in the water. The reason the gummy in the water expanded is that the movement of the water molecules into the gummy bears made it expand. Osmosis

Definition: Lift force is due to the development of high pressure under the hand and low pressure above it when the hand is pitched to the water at 40° (Amezdroz, et al,. 2010).

The amount of mass lost in the open system was larger than the closed system. As shown in the table, 1.2 grams was lost during the reaction in an open system compared to only 0.71 grams under a closed system. When observing the closed system, it was noticed that the balloon was rapidly expanding due to a particular gas forming. When the balloon was removed and a lit match was immediately placed on top of the conical flask, a gas that was within it extinguished the fire. This must have meant that the gas that was created during the reaction must have been one that was able to extinguish fire.

The purpose of our experiment is to see how salty it is for an egg to float. When salt is added to water, the mass of the water increases, and the water becomes denser. Objects will float better on a denser surface, they float better on salt water than they do fresh water. When you add table salt to water the salt dissolves and the water becomes denser, the volume increases by a small factor but the mass increases by a large factor. The salt is denser than water to begin with, because the salt has more mass than oxygen and hydrogen in the water molecules.

-The Reynolds number of this experiment was then calculated using equation (4) where c is the length of the aerofoil chord and is the dynamic viscosity of air.

2) State qualitatively why an incremental change in mass (i.e. 50 g) for the fully submerged case results in a different change in height, Δh, than the same incremental change in mass for the partially submerged case.

There is a balloon the shape and size of a beach ball. A string keeps it tethered to the ground. Someone in a white lab coat stands about eight feet away with a rod about as