Math 1201; College Algebra Mohamed Elsheshtawy University of the People June 22, 2016 Give an example of a function, f(x), with a domain of (0,5] and a range of [0,∞) f(x) =^(x-5)/^x 2. If f(t) = 2t – t2, what is (f(t + h) – f(t)) / h? f(t) = 2t – t^2 f(t+h) = 2(t+h) – (t+h)^2 =2t+2h-t^2-2th-h^2 f(t+h)-f(t)=(2t+2h-t^2-2th-h^2)-(2t – t^2) =2h-2th-h^2 and finally (f(t + h) – f(t)) / h=(2h-2th-h^2)/h=2-2t-h 3. If F = { (1,2), (3, 5), (4,7)} and G = { (1,4), (3,0), and (5, 2)}, what is F + G? What is F\G (using function arithmetic)? F = { (1+2), (3+ 5), (4+7)} = { (3) + (8) + (11)} = 22 G = { (1 +4), (3 + 0), and (5 + 2)} = { (5) + (3 ) + ( 7 )} = 15 F + G = 22 + 15 = 37 F/G= 1.4
($372 + $135 + 500) / ($2.21 - ($0.83 + .40)) = 1,028 [+/- 31]
2. Describe the pattern of growth in the “Number of people told” column for both Scenario A and Scenario B.
The solution is 0.25(15) + 0.25(35). The order in which the products are added does not matter. This is an example of using the commutative property.
A. -8 + x [(let x be the variable number, therefore sum of variable (x) and (-8) would be x-8 or -8 + x)]
The mean for the column “mean” is 3.56. It is very close to the parameter of interest but is not equal to it. You can calculate a confidence interval for the mean of the mean column, but a specific confidence interval would need to be provided. In that case, the confidence interval would be centered on 3.56, not 3.5.
If a car is going 60 miles per hour, how far will it go in feet in 1 minute?
numbers fit all of the rules that applied. I remembered that it could perfectly go into a group of
Also I still do not quit understand how this amounts to 8 ------> (1+1)**(5-2) = 8 why 2 * ? and what is the value?
| _____ 14. Tell whether the sequence 13, 0, 1, -2… is arithmetic, geometric, or neither.
3 x 2 + -2 x 4 + 3 x 8 + -2 x 1= 6 -8 +24 -2= 20
The average number of breakdowns from the simulation trials was 1.93 with a standard deviation of 0.20. No. of breakdowns per week
= (2t + 2h – t 2 – 2th – h 2 – 2t + t 2 ) = //2t – 2t = 0; t2– t2 =0
2(X4 + X5 + X6 + X7 + X10 + X11 + X16 + X17 + X18 + X27 + X28) – (X1 + X2 +X3
–x3 – x5 + x13 + x14 + x22 + x23 + x24 = 0
At t = 1, the value of the index is: ($95 + $45 + $110)/3 =