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ECT114 Week3 Homework Essay

Satisfactory Essays

ading Summary
These are the automatically computed results of your exam. Grades for essay questions, and comments from your instructor, are in the "Details" section below.
Date Taken:
7/24/2014
Time Spent:
5 h , 44 min , 39 secs
Points Received:
20 / 26 (76.9%)
Number of Attempts:
0

Question Type:
# Of Questions:
# Correct:
Multiple Choice
15
12
Matching
1
1

Grade Details - All Questions

Question 1.
Question :
(TCO 3) Determine the Boolean expression at TP1 with respect to the corresponding inputs.

Student Answer:

Instructor Explanation:
TP1 is the output of an OR gate. The Boolean operator for the OR gate is + and the inputs are A and B. Refer to Chapter 3 of the textbook for more information.

Points …show more content…

Points Received:
2 of 2 Comments:

Question 10.
Question :
(TCO 3) Determine the correct output waveform for the circuit below.

Student Answer:

YOptionA

YOptionB

YOptionC

YOptionD Instructor Explanation:
Y should be HIGH (when A = 0 AND B = 1) OR (when C NAND = 1). YOptionD is the only waveform that meets those criteria.

Points Received:
2 of 2 Comments:

Question 11.
Question :
(TCO 3) Determine the Boolean expression at TP1 with respect to the corresponding inputs.

Student Answer:

Instructor Explanation:
TP1 is the output of an XOR gate. The Boolean operator for the AND gate is  and the inputs are A and B. Refer to Chapter 3 of the textbook for more information.

Points Received:
1 of 1 Comments:

Question 12.
Question :
(TCO 3) Determine the Boolean expression at TP2 with respect to the corresponding inputs.

Student Answer:

Instructor Explanation:
TP2 is the output of an XNOR gate. The Boolean operator for the XNOR gate is , the XNOR gate requires an inversion bar over the entire expression, and the inputs are C and. Refer to Chapter 3 of the textbook for more information.

Points Received:
1 of 1 Comments:

Question 13.
Question :
(TCO 3) Determine the VHDL assignment statement at X with respect to the inputs.

Student Answer:

X <= (A XOR B) OR NOT (NOT B OR C);

X <= (A XOR B) OR (NOT B NOR C);

X <= (A XOR B OR NOT B OR

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