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Kinematics
Maxwell Mueller
1/21/2022
Activity 1: Graph and interpret motion data of a moving object
Activity 1. Table 1
Time (x axis) (seconds)
Position (y axis)
(meters)
0
0
5
20
10
40
15
50
20
55
30
60
35
70
40
70
45
70
50
55
Insert your graph here for Distance vs Time of a Moving Object.
Questions for Activity 1
Question 1:
What is the average speed of the train during the time interval from 0 s to 10 s?
4 m/s
Question 2:
Using the equation: v
=
s
2
−
s
1
t
2
−
t
1
, calculate the average speed of the train as it moves from position x = 50m to x = 60m.
.66666 m/s
Question 3:
What does the slope of the line during each time interval represent?
Acceleration
Question 4:
From time t = 35 s until t = 45 s, the train is located at the same position. What is slope of the line while the train is stationary?
0
Question 5:
Calculate the average speed of the train as it moves from position x = 70m to x = 55m. What does the sign of the average velocity during this time interval represent? -3m/s, The negative average velocity means the train is moving toward it’s original position during that interval.
Question 6:
What is the displacement of the train from time t = 0s until t = 50s?
55 m
Question 7:
What is the total distance traveled by the train from time t = 0s until t = 50s?
85 m
Question 8. What is the slope of the line during the time interval t = 45 to t = 50?
-3
Question 9: What does the sign of the slope in question 8 represent in terms of the motion of the train?
The negative sign means that the train is moving towards its original position.
Question 10: What is the average velocity of the train during the interval t= 0s to t = 50s?
1.1 m/s
Question 11: Does the train’s average velocity during the interval t= 0s to t = 50 s provide a complete picture of the train’s motion during this time?
Looking at only the average velocity during this time would not account for the
period in which was stationary or in which the train was moving back toward its
original position. The average velocity for the interval is positive and that would.
be misleading as to the actual motion of the train during this interval.
Activity 2. Calculate the velocity of a moving object.
Activity 2. Table 1
Time (s)
Displacement (m)*
0
0.77
1.55
2.51
3.26
4.00
4.76
5.50
6.24
*Note that 0.25 m = 25 cm
Insert a graph of Table 1 here. Include a chart title, axes titles and units.
Your preview ends here
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Related Questions
docs.google.com a
If a car changes speed from 20 m/s to 22
m/s in 10 seconds, its average acceleration
is *
20 m/s2
2 m/s2
0.2 m/s2
22 m/s2
21 m/s2
Which of the following is considered to be
an "accelerator" in an automobile? *
All of them.
gas pedal
steering wheel
brake pedal
non of them
On acceleration-time graph, a horizontal
...
10
O O O
O O
arrow_forward
O His movement stopped.
O His time was constant.
O His acceleration was positive.
Question 6
Velocity vs Time
Time (sec)
Based on the graph of velocity over time, which could be the initial velocity and the final velocity for this graph?
O initial = 2.5 m/s; final = 2.5 m/s
O initial = 0 m/s; final = 2.5 m/s
O initial = 3.0 m/s; final = 6.0 m/s
O initial = 6.Om/s: final = 3.0 m/s
Velocity (m/s)
arrow_forward
LEGO
tade
27. Determine the instantaneous acceleration values for each time, then plot the data on the provided grid.
Instantaneous
Average
Speed
(m/s)
Time
Position
Acceleration
2.5
Velocity
2. Vave
(m/s)
0.50
(s)
(m)
(m/s3)
2.0
1.0
0.25
0.25
1.5
2.0
1.00
0.50
1.00
1.0
3.0
2.25
0.75
1.50
4.0
4.00
1.00
2.00
0.50
5.0
6.25
1.25
2.50
1.0
2.0
3.0
4.0
5.0
Time (s)
Acceleration (m/s2)
arrow_forward
For the Following question Graph all 4 : [I just need all 4 graphs and please explain and make clean solution]
Position vs time
Velocity vs time
Acceleration vs time
Force vs time
[For your convenience, I have solved the numerical solutions for the problem] (Please Look at the picture since it is much cleaner)
Question : A 550 kilogram mass initially at rest acted upon by a force of F(t) = 50et Newtons. What are the acceleration, speed, and displacement of the mass at t = 4 second ?
a =(50 e^t)/(550 ) [N/kg]
v = ∫_0^t▒(50 e^t )dt/(550 )= v_0 +(50 e^t-50)/550=((e^t- 1))/11
x = ∫_0^t▒(e^t- 1)dt/(11 )= x_0 +(e^t- t - 1)/(11 )
a(4s)=(50*54.6)/550= 4.96[m/s^2 ]
v(4s)=((e^4-1))/11= 4.87[m/s]
x(4s)=((e^4- 4 - 1))/11= 4.51 [m]
arrow_forward
An inclined straight line in an s-t graph means:
The object is not in motion.
Velocity is constant.
Acceleration is constant.
Erratic motion takes place.
arrow_forward
25. A student wants to perform an experiment where they have to measure the time interval for
a ball bearing rolling down a slope (as with your first practical), in order to determine the
acceleration on the ball-bearing. They take 1 measurement for every distance (they move the
end of the measuring equipment 10 cm further way every time), and then they plot a graph.
This graph comes out with very scattered values that do not form a straight line at all. What
could be the reason for this? Choose all correct answers.
A. They should have taken more than one measurement at every distance.
B. The stopping wires might have malfunctioned sometimes, so they should have made sure
that the stopping wires only touched the metal when the ball bearing rolled over it.
C. The graph is fine with only one value measured per distance. It is the acceleration that was
not consistent. Nothing needs to be changed.
D. The graph axes need to be adjusted to make the data show a straight line.
arrow_forward
GRAPHING MOTION
(AREA)
1. In which section(s) is the cart
accelerating? (a-b,b-c,c-d,d-e,e-f,f-g)
60
E 40
2. In which section(s) is the cart not moving?
(a-b,b-c,c-d,d-e,e-f,f-g)
20
10
20 30 40 50 60 70
t (s)
3. In which section(s) is the cart moving backwards? (a-b,b-c,c-d,d-e,e-f,f-g)
4. What is the velocity of the cart in these sections?
a-b
c-d
e-f
f-g
(w) p
arrow_forward
1a) Plot the position in the x-direction as a function of time for both birds on the same co-ordinatesystem (the plots do not have to be exact).b) Write down the equations of motion in x and y directions for bird 1 and 2.
c)Using ?⃗ଵ(?) and ?⃗ଶ(?) to represent the position vector of birds 1 and 2, respectively, write downthe components of the position vector for both birds in parenthesis format.d) Write an equation using the tangent of the position vectors that describes when the huntershould release the arrow.e) Solve this equation for the time at which the hunter should release his arrow
PLEASE explain, especially 1c, d, and e
arrow_forward
Q1:
The graph below shows the acceleration of a hydraulic elevator in a four story school
building as a function of time.
hydraulic elevator - acceleration (m/s²) vs. time (s)
+0.8
+0.6
+0.4
+0.2
0
-0.2
-0.4
-0.6
-0.8
5
c. velocity-time
d. position-time
10
15
The graph begins at t = 0 s when the elevator door closed on the second floor and ends
at t = 20 s when the door opened on a different floor. Assume that the positive directions
for displacement, velocity, and acceleration are upward. Determine...
a. the maximum speed of the elevator
b. the duration of the brief jerk experienced by the elevator centered on 17.5 s
Sketch the corresponding graphs of...
Determine...
e. the most likely floor on which the elevator stopped
20
arrow_forward
The graph to the right shows velocity vs. time for a cart on a track with a friction pad attached. The cart
was launched from rest by a hoop spring. Use this graph to answer the following question: so long as the
ramp is level, even with the friction pad NOT in contact with the track it is impossible to produce a region
"b" that is flat (horizontal), i.e. that shows a constant velocity. This is because
b
V
a
of errors inherent to the motion detector
the acceler
tion
gravity causes the cart to
rate
air currents in the room significantly affect the motion of the cart
there is still a small amount of friction between the wheels of the cart and the track, and the axels of
the cart with the body of the cart
achieving constant velocity is not physically realistic under any circumstances
arrow_forward
What is the displacement based on the
following graph?
Position vs. Time
20
12
-5.0 m
15.0 m
-0.5 m
2.0 m
arrow_forward
Part A
The a – s graph for a rocket moving along a straight track has been
experimentally determined. The rocket starts at s = 0 when v = 0.
(Figure 1)
Determine its speed when it is at s = 85 ft
Express your answer to three significant figures and include the appropriate units.
HA
?
Value
Units
v =
Submit
Request Answer
Part B
Determine its speed when it is at s = 150 ft. Use Simpson's rule with n = 100.
Express your answer to three significant figures and include the appropriate units.
HA
Figure
v =
Value
Units
a (ft/s?)
Submit
Request Answer
< Return to Assignment
Provide Feedback
a = 5 + 6(y5 - 10)3
s (ft)
100
P Pearson
arrow_forward
QUESTION 2
The graph below represents the distance-time relationship from Justin and Nicole as they cycled on a road
from mile marker 291 to mile marker 298
3
2.5
2
+5
1
0.5
Justin's distance-time relationship
Nicole's distance-time relationship
-3-201 1 2 3 4 5 6 7 8 9 1011121314151617181920
Note that the horizontal axis represents time elapased (in minutes) since passing mile marker 291 and the
vertical axis represents the disance traveled (in miles) since passing mile marker 291.
a) How does the distance traveled and time elapsed compare for Nicole and Justin as they traveled from
mile marker 291 to mile marker 298 ?
b) How do Nicole's and Justin's speeds compare as they travel from mile marker 291 to mile marker 298
?
c) How do Nicole's and Justin's average speeds compare over the time interval as they traveled from mile
marker 291 to mile marker 298 ?
d) Do Nicole and Justin collide on the course 18 minutes after they passed mile marker 291 ? Explain your
answer.
arrow_forward
Velocity (m/s)
50
40
30
20
10
Time
4
6
8
10
12
14
(s)
The diagram above shows the journey of a train plotted as a velocity-time graph. Find:
a) The acceleration on the first part of the journey
b) The total distance covered in the first 10 seconds
c) The amount of time that the train is travelling at constant velocity
arrow_forward
B.
C 15.0 m
D 16.0r
E 20.01
Which of the following charts
TSTS
shows a uniform velocity of a
4 5 Time (s)
body in motion?
length of tape/cm
3
of the body is
4.
velocity/m
10 20 30 40 50 60 70
number of ticks
gure 4 shows
object.
1 length of tape/lam
8.
6.
A veloc
shown
follow
time/s
10 20 30 40 S0 60 70
number of ticks
12 14
motio
length of tapelcm
A T
nce moved
n it travels
ity?
80 m
160 m
8.
B.
6.
D
10 20 30 40 5O 60 70
number of ticks
arrow_forward
1. The wheel starts rotating from rest,
2) if its angular velocity Was a function of angular position 0 is W=0.1-0², where
O is in radian, and its radius ris 0.2 m, what is the magnitude of the angular
acceleration (in rad/s?) of the wheel after the wheel has turned 1.1 revolution(s) from
rest. Please pay attention: the numbers may change since they are randomized. Your
answer must include 2 places after the decimal point.
P
arrow_forward
An object is moving along a number line and its
position in time is determined by a cubic function
s(t) where time, t, is in seconds and position, s, is in
metres. The graph of s(t) is given below.
24
16
8
-8
-16
a. During what time interval(s) the object is moving
in the negative direction of the number line? Justify
your answer.
b. At what time is the object momentarily at rest
(motionless)? Justify your answer.
c. During what time intervals is the velocity of the
object negative? Justify your answer.
d. During what time intervals is the velocity of the
object increasing, i.e., the object is accelerating?
Justify your answer.
arrow_forward
Q1: Draw the orthographic Projections of given object.
20,26 20
R20
35
Q2: Draw the orthographic Projections of given object.
10
20
25
50
2/3
Q3: Draw the Full Sectional Front view and Top View of given object
100
40
70
2 HOLES
-016
15
R50
12
110
15
100
650
10 15
worl
lo noitseib te
15
50
06
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(3) Use the following graph to answer the questions on this page. The total time is 0.4 seconds.
Area of a triangle = 0.5 × base × height
vertical
1500
.... horizontal
500
time (s)
0.2
-1000
(a) The subject has a body weight of 1000 N. What is the horizontal impulse generated, total
vertical impulse generated, and net vertical impulse generated? Show all of your work for full
credit
(b) If mass is -100kg, what is the change in horizontal and the change in vertical velocity?
Reaction Force (N)
arrow_forward
In a vehicle safety test, two vehicles are crashed into one another and a force sensor on one of
the vehicles records the following curve for the force that it experienced as a function of time.
Add to this graph a sketch of the force that the other car experienced as a function of time and
use these two curves to explain why momentum is conserved in all types of collisions.
Force (N)
(0,0)
Time (s)
arrow_forward
A mechanic changing a tire rolls a wheel along the ground towards the car. The radius of the
wheel is 42cm, and the speed of the wheel as it rolls is 2 revolutions per second.
Height Above Ground
(m)
radiu
HIDE
wheel spet
Time
The diagram above illustrates the vertical motion of a point on the tire over time. It is possible to model
the height of this point using a sinusoidal function of the form h(t)=-a sin[b(t-c)]+d.
a) Determine the length of time required for one revolution of the tire.
b) State the numerical value for each of the parameters a, b, c & d.
And write a function representing the motion of the point in the form h(t)= -a sin[b(t−c)]+d.
arrow_forward
1- 3D model with dimensions (SE or SW view) and
2- The 3D model's Top view
Note : use creo parametric to show
the above view
R30
R12
70
20
R20
40
20
26
024
24
R16
50
20
80
100
arrow_forward
For the position-time graph shown, pick the corresponding velocity-time graph.
Velocity
Position
Time (s)
Black dot line (right):
Red dot line (left);
Yellow solid line (right):
Cyan dash line (left);
Blue solid line (left):
Time (s)
Velocity
Time (s)
arrow_forward
The traffic volume data table below counts was taken on rural a highway during the
morning peak hour at (8:00-9:00 am) on Monday of a week.
Time periods (minute)
8:00-8:15 AM
8:30-9:00 AM
Number of vehicles
385
790
The average time headway (sec) during
8:00-9:00 am
2.25
a) Find the traffic volume for the period from 8:15 to 8:30 am.
b) Determine the hourly volume (HV), the maximum rate of flow within the hour, and
the peak hour factor (PHF).
c) Estimate the density and speed of traffic if an average spacing of 150 ft.
d) Estimate the daily volume for Monday if the hourly expansion factor (HEF) is 22.05.
arrow_forward
Activity No. 1: Graphing Motion: Let's Move
Table 1
Distance, d
(km)
Time, t
I. Determining Slope on a Motion Graph
A. Displacement-Time Graph
1. Plot the given tabulated data (distance-time, d-t)
from Table 1.
(h)
50
1
100
2
100
3
100
4
150
100
6.
50
7
8.
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M Inbox (58) - tasin5 x
M It's official. Your p X
My Questions | ba x
G Security Checkup x
G Privacy Checkup
M Inbox (58) - tasin x
M New assignment: X
A Term Paper (Sectic X
+
i classroom.google.com/u/1/c/NDA5NTY×OTA5MZU0/a/NDAyNTUyNDIzNzk5/details
E Apps M Gmail
YouTube
A Maps
E Reading list
Term Paper Question
= Final Exam of ME 331
Determine the natural frequency of the system which is shown below. Here, springs geometries
O Term Pa
are similar but spring 1 made of mild steel, spring 2 made of copper, d= 5 mm, spring index = 10,
Assigned
Md Maruf Billah •
number of active coils in the springs = 8, m2= mo, r2=r¡ = 25 mm = 0.4R = 5t and the pulleys are
100 points
made of cast iron. Take other information which are necessary to solve the problem from
dd or create
internet/literature/book.
rk as done
mments
Class comme
k2
to Md Maruf Billah
m.
Add a class comm
m2
k1
Center line
Cross section of the springs
Cross section of the pulleys
Page
1 | 1
2:03 РМ
Type here to search
33°C Rain…
arrow_forward
Part III Capstone Problem
Interactive Physics - [Lab7Part3.IP]
Eile Edit World View Object Define Measure Script Window Help
Run StoplI Reset
圖|& 品凸?
Time
Length of Spring 22
6.00
dx
Center of Mass of Rectangle 2
5.000
Tension of Rope 3
Jain@
IFI
... N
ot
rot
***lad
Split
4.000
Velocity of Center of Mass of Rectangle 2
Vx Vx
V Vy
MM
Ve
- m/s
m/s
3.00
*** m/s
Vo
..* lad/s
2 00
Center of Mass of Rectangle 1
1.000
tol
rot
*.* rad
EVelocity of Center of Mass of Rectangle 1
Vx Vx
VVy
M
0.000
-m/s
w 30
m/s
w..
MI
Ve
母100
*** m/s
Vo
... rad/s
+
EAcceleration of Center of Mass of Rectangle 1
Ax Ax
A Ay
AUJAI
Ae
--- m/s^2
... m/s^2
-- m/s^2
.-- rad/s^2
3.00
Aø
Mass M1 = 2.25 kg is at the end of a rope that is 2.00 m in length. The initial angle with
respect to the vertical is 60.0° and M1 is initially at rest. Mass M1 is released and strikes M2
= 4.50 kg exactly horizontally. The collision is elastic. After collision, mass M2 is moving on
a frictionless surface, but runs into a rough patch 2.00…
arrow_forward
3. Use the graph of velocity vs. time below to answer the following questions. Each segment shown is
represented
by a straight line between two points.
Velocity, m/s
275
26
20
18
16
14
12
10
6420
10
Magnitude rounded to 3 sig. fig.
Velocity vs. Time
20
Magnitude rounded to 3 sig. fig.
40
30
Time, seconds
a. What is the change in position during the interval 0 ≤ t ≤ 20 s? Show your work.
Units
50
60
Units
70
b. What is the constant acceleration during the interval 20 ≤ t ≤ 40 s? Show your work.
arrow_forward
sample calculations
目
File Edit View Insert Format Data To
100%
$ % .0
.00 12:
fx |
A
1
Variable
Value
Units
diameter
height
m
4
volume
m^3
3
The image above shows a section of a Google sheet. What formula should be written in cell
B4 to calculate the volume of a cylinder with a diameter value in B2 and height in B3?
a) =0.25*PI()*B2^2 * B3
b) =PI()*B2^2 * B3
c) =pi*diameter^2 * height
d) =PI*B2^2 * B3
3 5
arrow_forward
Name
ASsignment ES
MTH 175 (Cameron)
8.4 Vector Models
Tutoring Assistance Permitted
#17. An airplane has an airspeed of 884 kilometers per hour bearing N53°E. The wind
velocity is 66 km/hour in the direction of N38°W.
a)
Write vectors (to the nearest tenth) representing the airplane A, the
884 km/hr
wind W, and the aircraft relative to the ground R.
66 km/hr
389
1532
A =
W
R
arrow_forward
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Related Questions
- docs.google.com a If a car changes speed from 20 m/s to 22 m/s in 10 seconds, its average acceleration is * 20 m/s2 2 m/s2 0.2 m/s2 22 m/s2 21 m/s2 Which of the following is considered to be an "accelerator" in an automobile? * All of them. gas pedal steering wheel brake pedal non of them On acceleration-time graph, a horizontal ... 10 O O O O Oarrow_forwardO His movement stopped. O His time was constant. O His acceleration was positive. Question 6 Velocity vs Time Time (sec) Based on the graph of velocity over time, which could be the initial velocity and the final velocity for this graph? O initial = 2.5 m/s; final = 2.5 m/s O initial = 0 m/s; final = 2.5 m/s O initial = 3.0 m/s; final = 6.0 m/s O initial = 6.Om/s: final = 3.0 m/s Velocity (m/s)arrow_forwardLEGO tade 27. Determine the instantaneous acceleration values for each time, then plot the data on the provided grid. Instantaneous Average Speed (m/s) Time Position Acceleration 2.5 Velocity 2. Vave (m/s) 0.50 (s) (m) (m/s3) 2.0 1.0 0.25 0.25 1.5 2.0 1.00 0.50 1.00 1.0 3.0 2.25 0.75 1.50 4.0 4.00 1.00 2.00 0.50 5.0 6.25 1.25 2.50 1.0 2.0 3.0 4.0 5.0 Time (s) Acceleration (m/s2)arrow_forward
- For the Following question Graph all 4 : [I just need all 4 graphs and please explain and make clean solution] Position vs time Velocity vs time Acceleration vs time Force vs time [For your convenience, I have solved the numerical solutions for the problem] (Please Look at the picture since it is much cleaner) Question : A 550 kilogram mass initially at rest acted upon by a force of F(t) = 50et Newtons. What are the acceleration, speed, and displacement of the mass at t = 4 second ? a =(50 e^t)/(550 ) [N/kg] v = ∫_0^t▒(50 e^t )dt/(550 )= v_0 +(50 e^t-50)/550=((e^t- 1))/11 x = ∫_0^t▒(e^t- 1)dt/(11 )= x_0 +(e^t- t - 1)/(11 ) a(4s)=(50*54.6)/550= 4.96[m/s^2 ] v(4s)=((e^4-1))/11= 4.87[m/s] x(4s)=((e^4- 4 - 1))/11= 4.51 [m]arrow_forwardAn inclined straight line in an s-t graph means: The object is not in motion. Velocity is constant. Acceleration is constant. Erratic motion takes place.arrow_forward25. A student wants to perform an experiment where they have to measure the time interval for a ball bearing rolling down a slope (as with your first practical), in order to determine the acceleration on the ball-bearing. They take 1 measurement for every distance (they move the end of the measuring equipment 10 cm further way every time), and then they plot a graph. This graph comes out with very scattered values that do not form a straight line at all. What could be the reason for this? Choose all correct answers. A. They should have taken more than one measurement at every distance. B. The stopping wires might have malfunctioned sometimes, so they should have made sure that the stopping wires only touched the metal when the ball bearing rolled over it. C. The graph is fine with only one value measured per distance. It is the acceleration that was not consistent. Nothing needs to be changed. D. The graph axes need to be adjusted to make the data show a straight line.arrow_forward
- GRAPHING MOTION (AREA) 1. In which section(s) is the cart accelerating? (a-b,b-c,c-d,d-e,e-f,f-g) 60 E 40 2. In which section(s) is the cart not moving? (a-b,b-c,c-d,d-e,e-f,f-g) 20 10 20 30 40 50 60 70 t (s) 3. In which section(s) is the cart moving backwards? (a-b,b-c,c-d,d-e,e-f,f-g) 4. What is the velocity of the cart in these sections? a-b c-d e-f f-g (w) parrow_forward1a) Plot the position in the x-direction as a function of time for both birds on the same co-ordinatesystem (the plots do not have to be exact).b) Write down the equations of motion in x and y directions for bird 1 and 2. c)Using ?⃗ଵ(?) and ?⃗ଶ(?) to represent the position vector of birds 1 and 2, respectively, write downthe components of the position vector for both birds in parenthesis format.d) Write an equation using the tangent of the position vectors that describes when the huntershould release the arrow.e) Solve this equation for the time at which the hunter should release his arrow PLEASE explain, especially 1c, d, and earrow_forwardQ1: The graph below shows the acceleration of a hydraulic elevator in a four story school building as a function of time. hydraulic elevator - acceleration (m/s²) vs. time (s) +0.8 +0.6 +0.4 +0.2 0 -0.2 -0.4 -0.6 -0.8 5 c. velocity-time d. position-time 10 15 The graph begins at t = 0 s when the elevator door closed on the second floor and ends at t = 20 s when the door opened on a different floor. Assume that the positive directions for displacement, velocity, and acceleration are upward. Determine... a. the maximum speed of the elevator b. the duration of the brief jerk experienced by the elevator centered on 17.5 s Sketch the corresponding graphs of... Determine... e. the most likely floor on which the elevator stopped 20arrow_forward
- The graph to the right shows velocity vs. time for a cart on a track with a friction pad attached. The cart was launched from rest by a hoop spring. Use this graph to answer the following question: so long as the ramp is level, even with the friction pad NOT in contact with the track it is impossible to produce a region "b" that is flat (horizontal), i.e. that shows a constant velocity. This is because b V a of errors inherent to the motion detector the acceler tion gravity causes the cart to rate air currents in the room significantly affect the motion of the cart there is still a small amount of friction between the wheels of the cart and the track, and the axels of the cart with the body of the cart achieving constant velocity is not physically realistic under any circumstancesarrow_forwardWhat is the displacement based on the following graph? Position vs. Time 20 12 -5.0 m 15.0 m -0.5 m 2.0 marrow_forwardPart A The a – s graph for a rocket moving along a straight track has been experimentally determined. The rocket starts at s = 0 when v = 0. (Figure 1) Determine its speed when it is at s = 85 ft Express your answer to three significant figures and include the appropriate units. HA ? Value Units v = Submit Request Answer Part B Determine its speed when it is at s = 150 ft. Use Simpson's rule with n = 100. Express your answer to three significant figures and include the appropriate units. HA Figure v = Value Units a (ft/s?) Submit Request Answer < Return to Assignment Provide Feedback a = 5 + 6(y5 - 10)3 s (ft) 100 P Pearsonarrow_forward
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