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Oct 30, 2023
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M3.6 Laboratory Report 8
10/22/23
PHY2053L
Purpose:
The purpose of this lab is to investigate the relationship between
force applied and the extension of a spring using the PhET simulation. The
experiment involves a single spring with a force constant of 200N/m in Part
1, two springs in parallel with the same force constant in Part 2 and exploring
elastic potential energy in Part 3. By conducting these experiments, I aim to
understand how the force applied affects the spring’s extension and explore
the concept of elastic potential energy stored in a spring.
Introduction:
Springs are ubiquitous in our daily lives, from the suspension
systems of vehicles to the functioning of everyday objects like doors and
mattresses. Understanding how springs respond to applied forces is essential
in various fields, including engineering and physics. Hooke’s Law, formulated
by the English scientist Robert Hooke in the 17
th
century, provides a
fundamental framework for comprehending the behavior of springs.
Procedure:
In the first part of the experiment, I used the PhET simulation to
measure the extensions from the equilibrium position. I did this by employing
a single spring with a force constant of 200 N/m. In the next part, I used the
Systems tab to capture the extensions of two springs arranged in parallel.
The next part the focus is shifted to determining the values of elastic
potential energy as well as the corresponding applied forces. These
calculations were based on the extension measurements provided by the
simulation. To visualize and analyze this data effectively, I used the Vernier
graphing tool, which enabled me to create graphs illustrating the relationship
between elastic potential energy and extension. Furthermore, I utilized this
graph to extrapolate the expected value of elastic potential energy at an
extension of 0.7 meters.
Data and Data Evaluation:
Part 1 – Using one spring of force constant 200 N/m
Force Applied (N)
Extension (m)
1 N
0.005 m
10 N
0.050 m
50 N
0.250 m
60 N
0.300 m
90 N
0.450 m
100 N
0.500 m
The magnitude of the applied force is contingent upon the spring’s
elongation. As the force acting on the spring increases, its length will
correspondingly increase in a direct proportion. In practical terms, for every 1
Newton of applied force, the extension is in a direct proportion of 0.005
meters. For example, when 50 N of force is applied, the resulting extension is
0.250 meters, and when 100 N of force is exerted, the extension extends to
0.500 meters.
Diagram:
Part 2 – Using two springs of force constant 200 N/m in parallel
Force Applied (N)
Extension (m)
1 N
0.003 m
10 N
0.025 m
50 N
0.125 m
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