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Computer Science
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Apr 29, 2024
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0.0.1
3.b. Comparing the Algorithms
Rank all three algorithms in order of how close the mean estimate was to the true mean. For the algorithm
that had the worst estimate, why do you think it had the worst estimate?
Limit your answer to
1-3
sentences
.
The first algorithm was the closest to the true mean, then algorithm 2 came in second and algorithm 3 had
the worst estimate. This is because Algorithm 3 introduces noise to each row individually, resulting in more
noise overall compared to Algorithm 2, which adds noise to the aggregated data. This increased noise level
can lead to larger errors in the estimate.
1
2
0.0.2
3.c. Practical Considerations
Both Algorithm 2 and Algorithm 3 are
𝜖
-differentially private, but have different performances for mean
estimation. Can you come up with a hypothetical practical scenario where you might want to use Algorithm
3 instead of Algorithm 2?
A scenario where Algorithm 3 might be preferred over Algorithm 2 is in a situation where individual-level
privacy is a higher priority than aggregate-level privacy. This can occur in a medical setting where patients
records are being analyzed for research purposes.
3
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Question 1
Suppose a large group of people in a room were all born in the same year. Consider the following three algorithms, which are each intended to identify the people in the room who have the
earliest birthday based on just the month and day. For example, a person born on February 10 is considered to have an earlier birthday than a person born on March 5. Which of the three
algorithms will identify the correct people?
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Correct answer will be upvoted else Multiple Downvoted. Don't submit random answer. Computer science.
You are given a parallel table of size n×m. This table comprises of images 0 and 1.
You can make such activity: select 3 distinct cells that have a place with one 2×2 square and change the images in these cells (change 0 to 1 and 1 to 0).
Your assignment is to make all images in the table equivalent to 0. You are permitted to make all things considered 3nm activities. You don't have to limit the number of activities.
It tends to be demonstrated that it is consistently conceivable.
Input
The principal line contains a solitary integer t (1≤t≤5000) — the number of experiments. The following lines contain portrayals of experiments.
The principal line of the depiction of each experiment contains two integers n, m (2≤n,m≤100).
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note:
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The english alphabet contains 26 letters: 21 consonants (including y) and 5 vowels.
The following scenario is inspired by the bath foam letters that are used by my toddler, here are the rules:
• there is only 1 of each letter with equal probability of being chosen.
• you will choose 4 letters at random without replacement and a word is formed in the order selected
• a valid word must also have no more than 2 consonants in a row
• words formed in this experiment may be valid under these rules even if they are not dictionary words in english
What is the probability of selecting a valid word?
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Suppose you have algorithms with five running times. Assume these are the exact running times. How much slower do each of these algorithms get when you (a) double the input or (b) increase the input size by one? Do both.
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The big O notation formula is f(n) = 0(g(n)).
(a) n2
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One drew a shut polyline on a plane, that comprised distinctly of vertical and even sections (corresponding to the arrange tomahawks). The sections switched back and forth among flat and vertical ones (an even fragment was constantly trailed by an upward one, as well as the other way around). The polyline didn't contain severe self-convergences, which implies that in the event that any two fragments shared a typical point, that point was an endpoint for the two of them (kindly counsel the models in the notes area).
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Input
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The primary line of each experiment contains one integer h…
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example of a chainword is the accompanying triple:
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the subsequent clue: one more succession of portions with the end goal that the letters that relate to each section spell a word from the word reference.
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Two occasions of chainwords are considered unique on the off chance that they have various strings, diverse first clues or distinctive second clues.
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Consider the following algorithms for determining whether anyone in the room has the same marks
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If anyone does have the same marks, they answer yes.
Algorithm 2: You tell the first person your marks and ask if they have the same marks; if
they say no, you tell the second person your marks and ask whether they have the same
marks; etc., for each person in the room.
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B. In the worst case, how many questions will be asked for each of the algorithms?
Page 1 of 2
C. For each algorithm, say whether it is constant, linear, or quadratic in the problem size in the
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place).
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algorithm. The first comparison is already given to you.
1
3
4
6
7
8
9
10
11
12
13
14
15
16
17
A
i
i
t
i
w
g
a
n
g
P =
S
t
i
Comparison #
i
T[i]
Pi]
1
g
2
3
4
O 4,4,n,n
9, 5, space, g
15,5,i,g
8,5,n,g
None of the above
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Given a sequence of integers A1, A2, ..., An (where the integers may be positive or negative), find a subsequence Aj, ... , Ak that has the maximum value of all possible subsequences.
The maximum contiguous subsequence sum is defined to be zero if all of the integers in the sequence are negative.
Consider the sequence shown below.
A1: -2 A2: 11 A3: -4 A4: 13 A5: -5 A6: 2
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Consider a second sequence, shown below.
A1: 1…
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Z = 1
Consider line function f(x,y) = 3x – 2y - 6+ Z, where Z is your student number
mod 3.
a) By using DDA algorithm,
b) By using Bresenham algorithm,
Show your steps and find the pixels to be colored between x = -1 and x=(4+Z).
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Given: NFA
1
q4
q3
q2
Using State Elimination Method, construct the regular expression equivalent to the given NFA. Add new start state q0 and new final state q1.
Eliminate state q2 first, then state q3, then state q4, and state q5 last.
Upon elimination of the four (4) states, the regular expression RE equivalent to the given NFA is
Sample Answer: 10*(10)*
NOTE: In your answer just use the exact number of parenthesis. That is, do not use extra parenthesis in your answer.
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